A canoe has a velocity of 0.420 m/sm/s southeast relative to the earth. The canoe is on a river that is flowing at 0.500 m/sm/s east relative to the earth. (Figure 1)

As seen from the Earth, the distance from Earth to the Sunis 1.50 × 10¹¹ m. A certain particle travels that distance in only 9.36 min. Answer the three questions below, using three sig figs. Part A - What is the speed of the particle, v, as seen from Earth? V= VE ΑΣΦ ? m/s

You have exactly 5 minutes 25 seconds to get to your next class on time and that classroom is 408 m east of where you are right now. First you run to your dorm room at an average velocity of 4.48 m/s to the south to pick up your calculator and your dorm room is 470 m south of where you were initially. What average velocity (magnitude only) do you now need to run from your dorm room to your classroom to arrive exactly on time?     1.92 m/s     4.48 m/s     2.83 m/s     2.70 m/s

A remote-controlled car is moving in a vacant parking lot. The velocity of the car as a function of time is given by = [5.00 m/s - (0.0180 m/s³)t²] i + [2.00 m/s + (0.550 m/s²)t]j. v = 7.00 Submit Previous Answers ✓ Correct Part D What is the direction (in degrees counterclockwise from +-axis) of the velocity of the car at t = 6.50 s? Express your answer in degrees. 0₂ = 52.7 ° Submit ✓ Part E a = Previous Answers Correct What is the magnitude of the acceleration of the car at t = 6.50 s? Express your answer with the appropriate units. 0.357 Submit μÀ m S ? Check the units used in your calculation; the numerical value you reached does not appear to have dimensions of acceleration. No credit lost. Try again. Previous Answers Request Answer