A cannon is fired at an angle of 48° with the horizontal. If the cannonball has an initial velocity of 611 feet per second, how far (horizontally) will the shot travel? Assume the initial height of the projectile is 0 feet, and neglect air resistance.

The highest barrier that a projectile can clear is 18.7 m, when the projectile is launched at an angle of 23.2° above the horizontal.  What is the projectile’s initial velocity (magnitude only since the angle is already given)?

A tennis ball is struck with an initial velocity of 30 m/s, 28 degrees above the horizontal.What is the vertical component of this initial velocity?

Kara is setting up a tee-shirt cannon for a community event. The angle of the cannon can be adjusted, but all projectiles leave the cannon at 25 meters per second. If Kara sets the angle of 20 degrees above the cannon to be above horizontal, what will be the range of the projectiles?

When throwing a ball, your hand releases it at a height of 1.5 m above the ground with velocity 6.8 m/s in direction 57° above the horizontal. (a) How high above the ground (not your hand) does the ball go?(b) At the highest point, how far is the ball horizontally from the point of release?

A projectile is shot in the air from ground level with an initial velocity of 490 m/sec at an angle of 60° with the horizontal. (a)At what time (in seconds) is the maximum range of the projectile attained? (b)What is the maximum range (in meters)?

A basketball player shoots toward a basket 6.2 m away and 3.0 m above the floor. If the ball is released 1.9 m above the floor at an angle of 48 degrees above the horizontal, what must the initial speed be if it were to go through the basket?

(a) From a balcony a child fires a toy arrow down to the ground below. The arrow has initial speed 12 m/s and is aimed at an angle of 30° below the horizontal. The arrow takes 1.2 seconds to hit the ground. (i) Calculate the initial horizontal (✰) and vertical (ŷ) velocity components of the arrow. (ii) Calculate the height of the balcony. (b) A projectile is launched with an initial speed of 75 m/s at an angle of 52° above the horizontal. If it lands at the same height from which it was launched, calculate how long the projectile remains in the air.

In a projectile motion experiment, the launcher is mounted horizontally at a height of 125 cm above the floor level. A sphere is shootout of the launcher and lands a horizontal distance of 176 cm away on the floor. What is the muzzle velocity? with the launcher mounted vertically,how high above the launch point would the sphere reach?

Consider a projectile launched at a height h feet above the ground and at an angle ? with the horizontal. If the initial velocity is v0 feet per second, the path of the projectile is modeled by the parametric equations x = t(v0 cos(?)) and y = h + (v0 sin ?)t - 16t2.Let h=6, v0=63.25, and ?=0.79.  What is the range of the projectile (i.e., how far does it travel? Round your answers to two decimal places).