(a) By using Fourier Transform properties and your approach of modeling the signals, determine the Fourier Transform of the signal given in Fig. 1. Do not use Fourier Integral directly. 91(t) C1 C1 t -C1 Figure 1: The signal for Q2 Part a. (b) Analyze the Fourier Transform of the signal given in the the previous part. List the properties you expected, and the properties that the Fourier Transform has. For example, one case would be if the Fourier Transform is conjugate symmetric.
(a) By using Fourier Transform properties and your approach of modeling the signals, determine the Fourier Transform of the signal given in Fig. 1. Do not use Fourier Integral directly. 91(t) C1 C1 t -C1 Figure 1: The signal for Q2 Part a. (b) Analyze the Fourier Transform of the signal given in the the previous part. List the properties you expected, and the properties that the Fourier Transform has. For example, one case would be if the Fourier Transform is conjugate symmetric.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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I want to ask the option b and it is related to option a. I already received the answer of the option a. I also attached its solution. Could you help me for option b?
Transcribed Image Text:(a)
By using Fourier Transform properties and your approach of modeling the
signals, determine the Fourier Transform of the signal given in Fig. 1. Do not use
Fourier Integral directly.
91(t)
C1
C1 t
-C1
Figure 1: The signal for Q2 Part a.
(b)
Analyze the Fourier Transform of the signal given in the the previous part.
List the properties you expected, and the properties that the Fourier Transform has.
For example, one case would be if the Fourier Transform is conjugate symmetric.
Transcribed Image Text:Step 1
For react function fourier Transform
s« (-)
F.T
W.width
F1
Area. Sa
2
= 2C,xl = -2C,
width
Area =
= 2C
F.T
-2C, . Sa (")
w.2C
F.T
-2C, Sa wci
dg(1)
= Fil?
di
we know that =
() - -(-)
(+- -
dF()
= jwF( w
di
Step 2
F(w) = G(w)
by eq. I and 2
ino{w) = -2c,sa(wa)
6(») =
G(w) = in(wci)
WCI
-2C, Sin(wa)
jw
-sin wCI
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