A bronze c86100 cylinder with diameter d2 = 60 mm is nestedinside a stainless steel tube with inner diameter of d₁ = 80 mmL = 250 mm and wall thickness of t = 10 mm. The bronzecylinder is 1 mm taller than the stainless steel tube. What isthe largest axial load, P, that can be applied without eithermaterial yielding?For this problem, use Eb = 103 GPa, Est=σY,br=345 MPa, σy,st = 207 MPa.193 GPa,APBL歌tBY NO SA2021 Cathy ZupkeThe maximum load before yielding is P =KN

Given the following figure and following parameters,d1=80 mmd2=60 mmt=10 mmL=250 mm Properties of…

Answered: A bronze c86100 cylinder with diameter…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The one end of a hollow square bar whose side is 10.47 in with 1.47 in thickness is under a tensile stress 102,500 psi and the other end is connected with a U bracket using a double-pin system. Find the minimum diameter of pin is used according to shear strength. Take the factor of safety as 1.5 and σallowable=243 ksi for pin material.
4. The stepped circular bar shown below is made from aluminum (E = 70 GPa, v = 0.35). Each segment is 400 mm in length. Prior to applying the loads, the bar has the dimensions shown. The structure is axially loaded as shown. Determine the stress in each segment, the maximum stress and its location, the final in length of the structure, and the final diameters of each segment due to the applied loads. All dimensions shown are in mm. Ø 25 40 15 ↑ Fu 300 kN 600 kN 300 kN
Problem 3. A solid round bar is to be assembled into a collar by press fitting. The inside radius of the collar is R = 50 mm and the outside radius is o = 4C mm. Find the maximum allowable radial interference 3 if the assembly is to have a safety factor of 2 against yielding. Both parts are made of carbon steel having E 200 GPa and Sy = 300MPa Solve using the DET. ↑ O
L = 0.3m A = 20 x 6 mm E= 70 GPa allowable stress = 120 MPa 0.6 m 0.4 m 0.2 m Rigid bar D C W 0.5m 40 x 6 mm 50 GPa wable stress = 80 MPa 16 mm dia. bolt with allowable s 6 mm 80 MPa in bearing and 60 MPa The rigid bar A,B,C,D shown in figure is connected to the ground by a hinge at B and to Magnesium bar at A, Aluminum bar at C. the properties of the bars are shown on the figure. all the connections are using 16 mm bolts in single shear. Determine the maximum safe load W that can be applied. Determine the final position of point D.
Question: Consider that the fit between the elements shown in the Figure below is H6/s5. They are both made of SAE 1340 OQT 1000 steel (Sy= 950 MPa, E = 200 GPa). Take D; = 75 mm and D, %3D %3D 90 mm. Determine the maximum possible value of the tangential stress at the inner surface of the outer element in MPa. NOTE: Answer is not 4750MPA. If you Submit This answer I will Directly report. |D, H6/s5 D. 6/7
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A steel rod with length equal to 12 ft, has a diameter of 0.8 inches in quarter of its length and a diameter of 0.4 inches the rest. If it is subjected to a tensile load of 6,500 lbs, what will be the total deformation of the bar if it has a modulus of elasticity E = 29.5 10^6 psi.
The pin-ended wrought-iron pipe shown in the figure below has outer diameter D, inside diameter d, and length L; it supports an eccentric load P based on a safety factor of n. Find the largest allowable eccentricity e. Given: D = 190 mm, d = 170 mm, L = 3.5 m, P = 430 kN, n = 1.4, E = 190 GPa, 0yp = 210 MPa.
Two cylindrical copper alloy bars have the same length L, but different shapes, as can be seen in the figure. The two bars are subjected to the same axial load P. Use the following numerical data: P = 1400 kN, L = 5 m, d = 80 mm, E = 110 GPa, and ν = 0.33. (a) Find the change in length of each bar. (b) Find the change in volume of each bar.
For 13 to 15. The compound bar carries the axial forces P and 2P. The working stresses are 40 ksi for steel and 20 ksi for aluminum, and the total elongation of the bar is not to exceed 0.2 in. 3 ft 4 ft 2P Steel Aluminum A = 0.6 in.² A=0.4 in.2 E = 29 × 106 psi E = 10 x 106 psi 13. What is the maximum allowable value for P? 14. Give the elongation of the steel section provided that the maximum allowable P is applied. 15. Give the elongation of the aluminum section provided that the maximum allowable P is applied.
q1 a
Steel bar with dimensions with (10mm and 10mm) subjected to axial load of * 2000N. Determine the stress P 10mm 10mm L=100 mm

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