College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Please answer ASAP for like.. Please ?arrow_forwardCan you please answer these. In the previous question the acceleration was found to be a= 1.675 Question 5 The situation for this problem is as explained in question 4. Block E is moving up and to the left (and Block D is moving down). The mass of Block D is 3.2 kg. The mass of Block E is 2.4 kg. The coefficient of kinetic friction between Block E and the plane is 0.5. The inclined plane is inclined at an angle of θ = 32 degrees above horizontal. Calculate the tension in the string (in units of newtons). Question 7 This question is the same as question 5 with the exceptions that The numbers have changed, and Block E is moving down and to the right (this refers to velocity) Block E is moving down and to the right (and Block D is moving up). The mass of Block D is 2.9 kg. The mass of Block E is 3.9 kg. The coefficient of kinetic friction between Block E and the plane is 0.41. The inclined plane is inclined at an angle of θ = 31 degrees above horizontal. Calculate the acceleration of…arrow_forwardNEED HELP PLEASEarrow_forward
- please answer immediately and please show full solution with formulas and units.arrow_forwardPlease help me with this. Please show all your workarrow_forwardBlock 1 (20 kg) is pulled by a rope from left to right up a ramp which is inclined 50 degrees from the horizontal. The rope pulls on block 1 with a force of 400 N parallel to the surface of the inclined plane. The coefficient of kinetic friction between the block and the surface equals 0.4. (use g = 10 m/s2) On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class.Assume that the x-axis is parallel to the incline and positive in the direction up the incline.After completing the free body diagram, enter below each force and its x & y-components. FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + j N Tension force on block 1 by Rope T1R = i + j N Normal force on block 1 by Surface N1S = i + j N Frictional force on block 1 by Surface f1S = i + j N What is the acceleration a of block 1? a = i + j m/s2arrow_forward
- In the scaled diagram, two forces, F, and F, act on a 4.0-kilogram block at point P. Force F, has a magnitude of 12 newtons, and is directed toward the right. 4.0 kg F2 F, = 12.0 N (Drawn to scale) 28. Using a ruler and the scaled diagram, determine the magnitude of F, in newtons.arrow_forwardConsider the system shown in the figure.(Figure 1) Block A has weight 6.0 N and block B has weight 4.0 N. Once block B is set into downward motion, it descends at a constant speed. Assume that the mass and friction of the pulley are negligible. Part A Calculate the coefficient of kinetic friction u between block A and the table top. Express your answer numerically. View Available Hint(s) 1ν ΑΣφ ? μ= Request Answer Submit Figure 1 of 1 Provide Feedback A Barrow_forwardFind I and J values and please answer all parts of this question 3. Block 1 (10 kg) is setting on the floor of an elevator. The elevator is moving upward with an increasing speed and the magnitude of the acceleration is 2 m/s2. On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. (use g = 10 m/2) Remember that the x-component is the "i" component and the y-component is the "j" component. -NET force on Block 1 (round to nearest integer) Fnet1 = ——- i + ——- j N The DIRECTION of the net force on block 1 is in the same direction as its acceleration. If the elevator is moving upward with an increasing speed, then the direction of the block's acceleration is up (positive y-value). The MAGNITUDE of the net force on block 1 equals its mass times acceleration, which are both given in the problem. -FORCES on BLOCK 1 Weight force on block 1…arrow_forward
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