A block of mass M has a circular cut with a frictionless surface as shown. The block rests on the horizontal frictionless surfaced of a fixed table. Initially the right edge of the block is at x = 0, in a coordinate system fixed to the table. A point mass m is released from rest at the topmost point of the path as shown and it slides down. When the mass loses contact with the block, its position is x and the velocity is v. At that instant, which of the following option is/are correct? M m R R x=0 (a) The velocity of the point mass mis v = 2gR m M (b) The x component of displacement of the centre of mass of mR the block M is M + m 1+

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- A block of mass M has a circular cut with a frictionless surface
as shown. The block rests on the horizontal frictionless surfaced
of a fixed table. Initially the right edge of the block is at x = 0, in
a coordinate system fixed to the table. A point mass mis released
from rest at the topmost point of the path as shown and it slides
down. When the mass loses contact with the block, its position is
x and the velocity is v. At that instant, which of the following
option is/are correct?
M
R
(a) The velocity of the point mass mis v =
M + m
R
x=0
2gR
m
M
(b) The x component of displacement of the centre of mass of
mR
the block M is -
1+
Transcribed Image Text:- A block of mass M has a circular cut with a frictionless surface as shown. The block rests on the horizontal frictionless surfaced of a fixed table. Initially the right edge of the block is at x = 0, in a coordinate system fixed to the table. A point mass mis released from rest at the topmost point of the path as shown and it slides down. When the mass loses contact with the block, its position is x and the velocity is v. At that instant, which of the following option is/are correct? M R (a) The velocity of the point mass mis v = M + m R x=0 2gR m M (b) The x component of displacement of the centre of mass of mR the block M is - 1+
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