A block of mass 1.33kg is being pulled by a string parallel to the contact surface with a slowly increasing force. If the block remains stationary until the force reaches 14.3N, what is the static friction coefficient?

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter5: Newton's Laws Of Motion
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Problem 56PQ: A textbook rests on a movable wooden plank that is initially parallel to the ground. a. How does the...
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**Problem Statement:**

A block of mass 1.33 kg is being pulled by a string parallel to the contact surface with a slowly increasing force. If the block remains stationary until the force reaches 14.3 N, what is the static friction coefficient?

**Explanation:**

This scenario involves understanding the concept of static friction between the block and the surface it is on. The static friction coefficient (\(\mu_s\)) can be determined using the formula:

\[ F_{\text{static}} = \mu_s \times N \]

Where:
- \( F_{\text{static}} \) is the maximum static frictional force (14.3 N in this case).
- \( \mu_s \) is the static friction coefficient.
- \( N \) is the normal force (equal to the gravitational force on the block, i.e., mass \(\times\) gravity, \(1.33 \, \text{kg} \times 9.8 \, \text{m/s}^2\)).

The calculation involves balancing forces to find \(\mu_s\).
Transcribed Image Text:**Problem Statement:** A block of mass 1.33 kg is being pulled by a string parallel to the contact surface with a slowly increasing force. If the block remains stationary until the force reaches 14.3 N, what is the static friction coefficient? **Explanation:** This scenario involves understanding the concept of static friction between the block and the surface it is on. The static friction coefficient (\(\mu_s\)) can be determined using the formula: \[ F_{\text{static}} = \mu_s \times N \] Where: - \( F_{\text{static}} \) is the maximum static frictional force (14.3 N in this case). - \( \mu_s \) is the static friction coefficient. - \( N \) is the normal force (equal to the gravitational force on the block, i.e., mass \(\times\) gravity, \(1.33 \, \text{kg} \times 9.8 \, \text{m/s}^2\)). The calculation involves balancing forces to find \(\mu_s\).
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