A block attached to a spring performs a simple harmonic mo- tion described by x(t) = sin(wt - 90). The velocity of the block is given by 1 v(t) = 12 cm/s cos(4-t- 핑 S 2.1 Determine the amplitude of the simple harmonic motion 1P 3 cm OP 6 cm OP 12 cm OP OP OP ww | -X 2.3 Determine the velocity v(t) after a half period, T/2. 2P-6 cm/s OP 6 cm/s OP-3 cm/s OP 9 cm 2.2 How was the oscillation initially set in motion at t = 0 s? By compressing the spring to the negative amplitude and then releasing it By pulling the spring to the positive amplitude and the releasing it By giving the block a sharp hit when the spring is at its equilibrium position 2PM By pulling the spring to a negative displacement value and then giving it a quick hit in the positive x-direction t #0 OP 3 cm/s 2.4 At what time does the object reach the equilibrium position for the first time? 2P 0.26 s OP 0.78 s OP 1.57 s OP 3.14 s 2.5 In which direction does the force of the spring point to at t = 0 s? OP along the negative x-direction Î 1Palong the positive x-direction OP at t=0s the spring is in its equilibrium position and there is no force on the mass exerted by the spring OP points perpendicular to the x-axis 2.6 At what time is the kinetic energy of the mass identical to the spring potential energy for the first time? 1P 0.065 s OP 0.24 s OP 0.36 s OP 0.46 s