A binary pulsar orbits with radial velocity 0.00004 times the speed of light. If the difference between the rest period and the minimum period over the course of the orbit is 0.001 ms, what is the rest period of the pulsar? 25 ms Trick question: this value cannot be calculated without more information 250 ms O 2.5 ms

1. Consider our Sun - it is in orbit around the center of our Milky Way Galaxy. The velocity of the Sun in its orbit is about 250 km/s. The distance to the center of the galaxy is about 9.1 kpc (kiloparsecs). We can use Kepler's third law to calculate the mass of the galaxy interior to the Sun's orbit. We assume that the orbit is circular so that the semimajor axis is just the radius of the circular orbit = 9.1 kpc. First we need to calculate the number of AU's in 9.1 kpc. (Note that 1 Крс - 1000 рс - 3260 1t yrs and 1 pc - 206,265 AU.) %3D a =r =9.1kpc = (9.1kpc) 1000 pc 206,265AU] 1kpc AU Sun 1pc

Using conservation of energy equation, solve for the mass of the apple mass of disk is 2.776kg mass of object*g*h=1/2(1/2*mass of disk*radius of disk^2)WB^2+1/2Mass of object VB^2 i need help please as musch as u can

The biggest black hole ever discovered has a mass of 40 billion solar masses. Calculate the Schwarzschild radius and compare it with the size of our Solar System.