A beam with rectangular cross section is show in figure. Using an admissible torsional shear stress of [7] = 118 MPa, determine the largest torque T in Newton-meter (Nm) that can be applied at end B. Please, give correct answer to one decimal place. 15 mm 45 mm B T

Below Figure shows the section of an angle purlin. A bending moment of 5 kN.m is applied to the purlin in a plane at an angle of 30 deg to the vertical y axis. If the sense of the bending moment is such that both its components Mx and My produce tension in the positive xy quadrant, calculate the maximum direct stress in the purlin, stating clearly the point at which it acts. * 100 mm E 10mm 30 C D -10mm 57 MPa. 89 MPa. Non Above O 72 MPa. 125mm

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Distance from point A to B 200mm, from B to C 200mm, and from C to D 200mm.

Q1. Figure below shows a simply supported beam that has a rectangular cross section 120 mm wide and 200 mm high. a. Determine the maximum bending stress in the beam. b. Calculate the bending stress experienced by a point on section B that is 25 mm below the top of the beam. (Consider the distance of this point from the N.A when solving this part) |15KN 6 kN/m B D 0.8 m 2 m 1.0 m R = 14 kN RE = 19 kN

The steel beam shown in the figure 2 is made by a steel type that has σY=250 MPa and σU=400MPa Determine the maxium torque that can be applied to the beam when it is bent aroung the x axis.

The simply supported beam is subjected to the force F = 700 N and the uniform distributed load with intensity w = 150 N/m. Draw the shear force and bending moment diagrams (in your homework documentation) and determine the equations for V(r) and M(x). Take a = 0 at point A. 19 F a Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 5.2 m 2.6 m 3.12 m Support Reactions The reaction at A is N. The reaction at D is N. Shear Force and Bending Moment Equations In section AB: V(x)= N and M(x)= N-m. In section BC: v(x)- N and M(x)= N-m. In section CD: V(x)- N and M(x)= N-m. A

Question 2 Derive the following formula for the distance e from the centreline of the wall to the (2 1) shear center S for the hat section of constant thickness shown in Figure Q2 3bh2 (b+2a)-8ba3 e = h2(h+6b+6a)+4a2(2a+3h) 0) Check the formula for the special case of channel section (a (2 2) 3 12 C e b Figure Q2 Hat-section wall ro N.

Please solved in typed form. The composite shaft, consisting of aluminum, copper, and steel sections, is subjected to the loading shown. The cross-sectional areas of sections AB, BC , and CD are AAB = 0.08in2 , ABC = 0.11in2 , and ACD = 0.04in2 , respectively. The modulus of elasticity for each section are shown in the figure. Neglect the size of collars B and C. Determine the displacement of B wrt C of the composite shaft? Image is uploaded for reference.