A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 36.2° and the angle of refraction is 25.0°, find the critical angle for the liquid when surrounded by air.

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Chapter1: Units, Trigonometry. And Vectors
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A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 36.2° and the angle of
refraction is 25.0°, find the critical angle for the liquid when surrounded by air.
Step 1
When light goes from one material into another having a higher index of refraction, the light bends toward the normal
line as shown in part (a) of the diagram.
02
air
liquid
(a)
(b)
We are given that when = 36.2°, the angle of refraction in the liquid is = 25.0°. Thus, from Snell's law, the index of
refraction of the liquid is
nliquid
=
nair
sin
sin e
=
(1.00) sin
sin 25.0°
0
(0.423)
Transcribed Image Text:A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 36.2° and the angle of refraction is 25.0°, find the critical angle for the liquid when surrounded by air. Step 1 When light goes from one material into another having a higher index of refraction, the light bends toward the normal line as shown in part (a) of the diagram. 02 air liquid (a) (b) We are given that when = 36.2°, the angle of refraction in the liquid is = 25.0°. Thus, from Snell's law, the index of refraction of the liquid is nliquid = nair sin sin e = (1.00) sin sin 25.0° 0 (0.423)
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