A beaker contains 100. mL of the buffer solution. What is the resulting pH when 50.0 mL of 0.4 M HNO3 is added to the buffer? H₂PO; HPO2- 0.50 M; 0.50 M Кан,род pH after strong acid added = [?] = 6.23 x 10-8 pH of Soln w/ Acid Enter

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### Buffer Solution pH Calculation Problem

**Problem Statement:**

A beaker contains 100. mL of the buffer solution. What is the resulting pH when 50.0 mL of 0.4 M HNO₃ is added to the buffer?

Buffer Components and Concentrations:
- \( \text{H}_2\text{PO}_4^- \) 
- \( \text{HPO}_4^{2-} \)
- Concentrations: 0.50 M for both components.

Acid Dissociation Constant:
\[ K_{\text{a}_{\text{H}_2\text{PO}_4^-}} = 6.23 \times 10^{-8} \]

**Objective:**
Determine the pH after the strong acid (HNO₃) is added to the buffer.

**Given Equation:**
\[ \text{pH after strong acid added} = \;? \]

**Interactive Element:**
- *Text Box:* "pH of Soln w/ Acid"
- *Button:* "Enter"

**Explanation for Calculation Approach:**

1. **Determine the moles of HNO₃ added:**
   \[ \text{Moles of HNO₃} = 0.4 \, \text{M} \times 50.0 \, \text{mL} = 0.4 \, \text{M} \times 0.050 \, \text{L} \]

2. **Calculate the initial moles of phosphate species in the buffer before the acid is added.**

3. **Use the moles of HNO₃ to determine the new equilibrium concentrations of \( \text{H}_2\text{PO}_4^- \) and \( \text{HPO}_4^{2-} \).**

4. **Apply the Henderson-Hasselbalch equation to find the new pH of the solution:**
   \[ \text{pH} = \text{pKa} + \log \left( \frac{[\text{base}]}{[\text{acid}]} \right) \]

Where, 
\[ \text{pKa} = -\log K_{\text{a}_{\text{H}_2\text{PO}_4^-}} \]

This example demonstrates the effect of adding a strong acid to a buffered system
Transcribed Image Text:--- ### Buffer Solution pH Calculation Problem **Problem Statement:** A beaker contains 100. mL of the buffer solution. What is the resulting pH when 50.0 mL of 0.4 M HNO₃ is added to the buffer? Buffer Components and Concentrations: - \( \text{H}_2\text{PO}_4^- \) - \( \text{HPO}_4^{2-} \) - Concentrations: 0.50 M for both components. Acid Dissociation Constant: \[ K_{\text{a}_{\text{H}_2\text{PO}_4^-}} = 6.23 \times 10^{-8} \] **Objective:** Determine the pH after the strong acid (HNO₃) is added to the buffer. **Given Equation:** \[ \text{pH after strong acid added} = \;? \] **Interactive Element:** - *Text Box:* "pH of Soln w/ Acid" - *Button:* "Enter" **Explanation for Calculation Approach:** 1. **Determine the moles of HNO₃ added:** \[ \text{Moles of HNO₃} = 0.4 \, \text{M} \times 50.0 \, \text{mL} = 0.4 \, \text{M} \times 0.050 \, \text{L} \] 2. **Calculate the initial moles of phosphate species in the buffer before the acid is added.** 3. **Use the moles of HNO₃ to determine the new equilibrium concentrations of \( \text{H}_2\text{PO}_4^- \) and \( \text{HPO}_4^{2-} \).** 4. **Apply the Henderson-Hasselbalch equation to find the new pH of the solution:** \[ \text{pH} = \text{pKa} + \log \left( \frac{[\text{base}]}{[\text{acid}]} \right) \] Where, \[ \text{pKa} = -\log K_{\text{a}_{\text{H}_2\text{PO}_4^-}} \] This example demonstrates the effect of adding a strong acid to a buffered system
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