A bead of mass m sits on a frictionless helical wire whose shape is given by x = 4 cos(8), 4 cos(0), y = 4 sin(0), z = -50. After the bead is released from rest at z = 0 it slides down due to the gravitational force Fg = -mg k. n b) What is the energy before it is released? E = m a) Denoting the speed of the bead as u, give the formula for the energy of this bead. E= -z = 0 V= c) Give the speed of the bead when it has rotated about the z- axis n times:

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A bead of mass m sits on a frictionless helical wire whose shape
is given by x = 4 cos(0), y = 4 sin(0), z = -50. After the bead
is released from rest at z = 0 it slides down due to the
gravitational force Fg =
= -mg k.
b) What is the energy before it is released?
E =
a) Denoting the speed of the bead as u, give the formula for the
energy of this bead.
E=
*
m
V=
Z=0
c) Give the speed of the bead when it has rotated about the z-
axis n times:
Here frictionless means that there is no loss of energy due to
reaction forces or air resistance.
Transcribed Image Text:A bead of mass m sits on a frictionless helical wire whose shape is given by x = 4 cos(0), y = 4 sin(0), z = -50. After the bead is released from rest at z = 0 it slides down due to the gravitational force Fg = = -mg k. b) What is the energy before it is released? E = a) Denoting the speed of the bead as u, give the formula for the energy of this bead. E= * m V= Z=0 c) Give the speed of the bead when it has rotated about the z- axis n times: Here frictionless means that there is no loss of energy due to reaction forces or air resistance.
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