A basic cellular package costs $20/month for 60 minutes of calling with an additional charge of $0.20/minute beyond that time. The cost function C (a) for using a minutes would be . If you used 60 minutes or less, i.e. if if a < 60, then C (a) = 20 (the base charge). . If you used more than 60 minutes, i.e. (z - 60) minutes more than the plan came with, you would pay an additional $0.20 for each of those (z - 60) minutes. Your total bill would be C(x)=20+0.20 (z - 60). If you want to keep your bill at $50 or lower for the month, what is the maximum number of calling minutes you can use? The maximum calling minutes you can use is Number minutes.

Given fixed costs of $37400, variable costs of (4x/9+333)and selling price in dollars per unit of (1467-5x/9), what is the break even point? what is the maximum revenue

A supply company charges for 90-liter drums using the demand function p(x)=20.9−1.6x  What is the revenue function?

Suppose the weekly cost C, in dollars, of eliminating p percent of the pollution from the emissions of a factory is given by the following. C(p) = 5600p/100-p   (a) What type of function is this? (multiple choice) A. rational function B. identity function C. linear function D. polynomial function E. power function   (b) Given that p represents the percent of pollution removed, what is the domain of C(p)? (Enter your answer using interval notation.)   (c) Find C(0). (multiple choice) Interpret its meaning. A. The factory will gain revenue if no pollution is removed. B. There is no cost if no pollution is removed. C. Removing all the pollution will have a large cost. D. Removing all the pollution will have no cost. E. Even if no pollution is removed, there will be some cost.   (d) Find the weekly cost (in dollars) of removing 99% of the pollution. $ ?