Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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**Problem:**

A balloon containing a sample of helium gas is warmed in an oven at constant pressure. If the balloon measures 1.25 L at room temperature (20.0°C), what is its volume at 90.0°C?

**Answer:**

To solve this problem, use Charles's Law, which relates the volume and temperature of a gas at constant pressure:

\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

Where:
- \( V_1 = 1.25 \, \text{L} \) (initial volume)
- \( T_1 = 20.0°C = 293 \, \text{K} \)
- \( V_2 \) is the final volume
- \( T_2 = 90.0°C = 363 \, \text{K} \)

Rearranging for \( V_2 \), we get:

\[ V_2 = V_1 \times \frac{T_2}{T_1} \]

Substitute the values:

\[ V_2 = 1.25 \times \frac{363}{293} \, \text{L} \]

Calculate \( V_2 \) to find the final volume.
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Transcribed Image Text:**Problem:** A balloon containing a sample of helium gas is warmed in an oven at constant pressure. If the balloon measures 1.25 L at room temperature (20.0°C), what is its volume at 90.0°C? **Answer:** To solve this problem, use Charles's Law, which relates the volume and temperature of a gas at constant pressure: \[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \] Where: - \( V_1 = 1.25 \, \text{L} \) (initial volume) - \( T_1 = 20.0°C = 293 \, \text{K} \) - \( V_2 \) is the final volume - \( T_2 = 90.0°C = 363 \, \text{K} \) Rearranging for \( V_2 \), we get: \[ V_2 = V_1 \times \frac{T_2}{T_1} \] Substitute the values: \[ V_2 = 1.25 \times \frac{363}{293} \, \text{L} \] Calculate \( V_2 \) to find the final volume.
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