A ballistic pendulum consists of a 3.3-kg wooden block originally at rest, 0 = 0°. When a 2-g bullet strikes and becomes embedded in it, it is observed that the block swings upward to a maximum angle of 0= 6° (Figure 1)

Question 5 A solid sphere of radius R = 0.15 m and mass m = 0.9 kg purely rolls with velocity v = 1.1 m/s along a horizontal surface before striking a low curb of height h = 0.05 m. The impact with the kerb can be assumed to involve no rebound so that the ball pivots about contact point P. The moment of inertia of the sphere is IG = (2/5) mR². Ө Calculate the following: (a) the angular velocity of the ball before impact; (b) the kinetic energy of the ball before impact; g G (c) the angular momentum of the ball around contact point P just before impact (CW +ve); hint: account for both linear and angular motion in the calculation A Moving to another question will save this response. (d) the angular velocity of the ball just after impact (CW +ve). hint: calculate the moment of inertia of the ball around point P using parallel axis theorem h T >>

A solid sphere of mass M and radius R rolls without slipping along a table at speed v. What is its kinetic energy? Mv2/5 Mv2/2 Mv2 3Mv2/2 7Mv2/10

Those data are for questions 15 to 20 The 5-lb rod AB with a length of l=2 ft is hanging in the vertical position. A 2-lb block , sliding on a smooth horizontal surface with a velocity of 10 ft/s, strikes the rod at its end B. e = 0.8. The goal is to find the linear velocity of the block and the angular velocity of the bar just after collision. Step 5: Find the linear velocity of the block after impact. Give your answer in ft/s with 1 decimal.