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**Projectile Motion with Air Resistance - Educational Exercise**

A ball with mass 0.45 kg is thrown upward with an initial velocity of 25 m/s from the roof of a building 40 m high. Assume there is a force due to air resistance of magnitude \( \frac{v^2}{1325} \) directed opposite to the velocity, where the velocity \( v \) is measured in m/s.

**NOTE:** Use \( g = 9.8 \, \text{m/s}^2 \) as the acceleration due to gravity. Round your answers to 2 decimal places.

**Exercise**

a) Find the maximum height above the ground that the ball reaches.

**Height:** \[ \_\_\_\_\_\_\_\_\_ \text{m} \]

b) Find the time that the ball hits the ground.

**Time:** \[ \_\_\_\_\_\_\_\_\_ \text{seconds} \]

c) Use a graphing utility to plot the graphs of velocity and position versus time.

**Graph Description:**

For part (c), ensure your graphing utility is correctly set up to display two graphs:
1. **Velocity vs. Time**: This graph should show how the velocity of the ball changes over time, considering both gravity and air resistance. Expect a curve that starts at 25 m/s, decreases to zero at the peak, and then becomes negative (indicating downward motion), eventually leveling off as it approaches terminal velocity while falling.
  
2. **Position vs. Time**: This graph represents the ball's height above the ground over time. The curve will start at 40 m (the height of the building), rise to a maximum height (found in part a), and then decrease until it reaches zero (when the ball hits the ground).

Your plotted graphs should properly represent these relationships to give a clear visual understanding of the ball's motion under the given conditions.
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Transcribed Image Text:**Projectile Motion with Air Resistance - Educational Exercise** A ball with mass 0.45 kg is thrown upward with an initial velocity of 25 m/s from the roof of a building 40 m high. Assume there is a force due to air resistance of magnitude \( \frac{v^2}{1325} \) directed opposite to the velocity, where the velocity \( v \) is measured in m/s. **NOTE:** Use \( g = 9.8 \, \text{m/s}^2 \) as the acceleration due to gravity. Round your answers to 2 decimal places. **Exercise** a) Find the maximum height above the ground that the ball reaches. **Height:** \[ \_\_\_\_\_\_\_\_\_ \text{m} \] b) Find the time that the ball hits the ground. **Time:** \[ \_\_\_\_\_\_\_\_\_ \text{seconds} \] c) Use a graphing utility to plot the graphs of velocity and position versus time. **Graph Description:** For part (c), ensure your graphing utility is correctly set up to display two graphs: 1. **Velocity vs. Time**: This graph should show how the velocity of the ball changes over time, considering both gravity and air resistance. Expect a curve that starts at 25 m/s, decreases to zero at the peak, and then becomes negative (indicating downward motion), eventually leveling off as it approaches terminal velocity while falling. 2. **Position vs. Time**: This graph represents the ball's height above the ground over time. The curve will start at 40 m (the height of the building), rise to a maximum height (found in part a), and then decrease until it reaches zero (when the ball hits the ground). Your plotted graphs should properly represent these relationships to give a clear visual understanding of the ball's motion under the given conditions.
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