A ball of mass m = 300 g is released from rest a at a height h = 45 cm above a vertical spring of force constant k as shown in figure a to the right. The ball strikes the top of the spring and compresses it a distance d = 15 cm as shown in figure b.

In the figure here, two children are playing a game in which they try to hit a small box on the floor with a marble fired from a spring-loaded gun that is mounted on a table. The target box is horizontal distance D = 2.23 m from the edge of the table. Bobby compresses the spring 1.16 cm, but the center of the marble falls 29.9 cm short of the center of the box. How far should Rhoda compress the spring to score a direct hit? Assume that neither the spring nor the ball encounters friction in the gun.

Imagine that you ski down a slope wearing a Velcro ski vest and then continue skiing on a horizontal surface a bottom of the hill. There you run into a padded, Velcro-covered cart, which is also on skis (see the figure below). A 1280-N/m spring is attached to the other end of the cart and also to a wall. The spring compresses after your 60-kg body hits and sticks to the 20-kg cart. Your speed is 16 m/s just before you hit the cart. (a) What is your maximum speed after joining with the cart? (b) What is the maximum compression of the spring? (c) What is the period of the vibrational motion? (d) What is your maximum acceleration and where does it occur? Sketch and translate Draw a labeled sketch. mYou = 60 kg VYou i x = 16 m/s %3D k =12Joyce AbdenCart 20 kg %3D Vfx = ? A = ? During vibrations T = ? %3D after collision amax = ?

A 3.00 kg box that is sliding on frictionless surface with a speed of 15 m/s approaches a horizontal spring. The spring has a spring constant of 1900 N/m. m 10000000 How far will the spring be compressed in stopping the box? Submit Answer Tries 0/10 How far will the spring be compressed when the box's speed is reduced to half of its initial speed? Note: This is not saying that the box starts with half of the original speed, the box still starts with 15 m/s, the question asks how far the spring will have been compressed when it has slowed the box to half of that speed. Submit Answer Tries 0/10

When a m = 12 kg mass is on a frictionless incline of 30 degrees and takes 270 N to compress a spring 2.0 cm: The block briefly stops when the spring is compressed to 5.5 cm a) How far did it travel. I found the answer is 35 cm b) What is the speed of the 12 kg block as it touches the spring? How do I do part b? I got the spring constant k = 13500 and used 1/2 kx^2 to find how many joules it has at compressing the spring to 5.5 cm. When I set that equal to 1/2 mv^2 I did not get the right answer. How would I go about finding b?

An inclined plane of angle θ has a spring of force constant k fastened securely at the bottom so that the spring is parallel to the surface. A block of mass m is placed on the plane at a distance d from the spring. From this position, the block is projected downward toward the spring with speed v as shown in the figure. By what distance is the spring compressed when the block momentarily comes to rest? There is no friction between the block and the surface. Express your answer in terms of g and the other symbols given.

A 1.1 N ball is shot horizontally out of a spring gun from a height of 0.9 and lands 2 m horizontally away from the gun. What is the spring constant in N/m of the spring which launched the ball if the ball compressed the spring 0.4 m?

Below is a conservation of energy problem. The solution to this problem is provided. Assess whether the solution provided is correct or incorrect AND EXPLAIN WHY. = 4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has a spring constant of k₁ 2750 N/m. After leaving the spring, it travels up a 28° incline to a height of 2.8 m. At the top of the hill is a second spring with a spring constant of k₂ = 350 N/m. The horizontal portions are frictionless, but the hill has a coefficient of kinetic friction equal to uk = 0.16. The final velocity of the block is 9.78 m/s. How much is the second spring compressed by when the block comes to a stop against it? Simplifies to X₁ = 0.40 m h₁ = 0 m Vi = 0 m/s xf Wnc = 0 J 2 Wnc + mgh₁ +1/2 kx₁² +½ mv² = mgh₁+½ kxf² +½ mvf2 = k₁ = 2750 N/m k₂= 350 N/m m = 4.6 kg 2 ½ k₁x₁² = mghf + ½ K₂Xf2 2 ½ k₁x;² — mghƒ _½ k₂xf² Xf= 2750 N/m 350 N/m (0.4 m)2 x k 2 2gh -X f= X₁ = ? m h₁ = 2.8 m Vi = 0 m/s 0.141 m 2(9.8…

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A ball of mass m = 1.85 kg is released from rest at a height h = 74.0 cm above a light vertical spring of force constant k as in Figure [a) shown below. The ball strikes the top of the spring and compresses it a distance d = 9.50 cm as in Figure [b] shown below. Neglecting any energy losses during the collision, find the following. (a) Find the speed of the ball just as it touches the spring. m/s (b) Find the force constant of the spring. KN/m Hwww