A ball is thrown straight up in the air with an initial velocity of 20.0 m/s. One second after it is released it is still moving upward in the air. At this time what is the magnitude of the acceleration of the ball (in m/s^2)? *Note that magnitudes are nonnegative quantities.

A web page designer creates an animation in which a dot on a computer screen has position 7 = [4.0 cm+ (2.5 cm/s²) t²] î + (5.0 cm/s) tj Part A Find the magnitude of the dot's average velocity between t = 0 and t = 2.0 s. Express your answer with the appropriate units. P V = Value Uav Submit Part B A αav = Request Answer Units Find the direction angle of the dot's average velocity between t = 0 and t = 2.0 s. The angle is measured counterclockwise from the +x-axis toward the +y-axis. Express your answer in degrees. ΠΑΣΦ ? ?

You qualitatively analyzed the motion of a van earlier. Now, using the example of the ball thrown into the air, you can do a more detailed analysis of the van's motion. The table shown here includes the time and position data, with one worked example for finding acceleration. Time Position Velocity Ad Acceleration t(s) (m/s) Ar (m/s") 0.0 0.0 6.0 2.0 12 +3.0 12 4.0 36 Sample Calculation Notice that the velocity that will be plotted at t = 1.0 s is the average velocity between t = 0.0 s and t 2.0 s. The velocity that will be plotted at t 3.0 s is the average velocity between t = 2.0 s and 4.0 s. The acceleration that will be plotted at t= 2.0 s is the average acceleration between t = 1.0 s and t = 3.0s. 6.0 48 8.0 96 10.0 142 12.0 190 14.0 226 16.0 250 Adgd-d 12 m-0.0 m 2.0 s-0.0 s V = 18.0 262 Alo2 t2-lo 12 m 2.0 s %3D Analyze and Conclude 1. How well do the average and instantaneous velocities that you calculated agree with = 6.0 m each other? 36 m-12 m V= Afz4 %3D %3D 2 Separate the…

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A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 6.25 m/s. The car is a distance d away. The bear is 21.3 m behind the tourist and running at 8.64 m/s. The tourist reaches the car safely. What is the maximum possible value for d? Vbear Number i Vtourist Units

The following graph depicts the velocity of someone playing tag over a short period of time. Use this velocity graph to answer the following questions. The person's maximum magnitude for velocity is 4.5 m/s in both the positive and negative directions.  A is at time point 3 seconds, B is at time point 4.5 seconds, C is at time point 5.5 seconds, D is at time point 7 seconds, E is at 8 seconds, F is at 9 seconds and G is at 10 seconds. What is the acceleration in meters/second2 (m/s2) at the 2 second mark of playing tag? What is the acceleration in meters/second2 (m/s2) at the 5 second mark?  What is the velocity in meters/second (m/s) at the 5 second mark?  What is the acceleration in meters/second2 (m/s2) at the 6.5 second mark?  What is the acceleration in meters/second2 (m/s2) at the 8.5 second mark?  What is the velocity in meters/second (m/s) at the 9.5 second mark?

A golf ball is dropped from rest from a height of 9.90 m. It hits the pavement, then bounces back up, rising just 6.30 m before falling back down again. A boy then catches the ball when it is 1.40 m above the pavement. Ignoring air resistance, calculate the total amount of time that the ball is in the air, from drop to catch. Number i Units

Starting from rest, the car is going 42 ft/s (29 mi/h) at the end of 4.5 s. What is the car's average acceleration in ft/s2? magnitude       ft/s2 direction      ---Select--- in the direction of motion opposite to the direction of motion  (b) In 3.5 more seconds, the car is going 84 ft/s (57 mi/h). What is the car's average acceleration for this time period? magnitude       ft/s2 direction      ---Select--- in the direction of motion opposite to the direction of motion  (c) The car then slows to 63 ft/s (43 mi/h) in 2.5 s. What is the average acceleration for this time period? magnitude       ft/s2 direction      ---Select--- in the direction of motion opposite to the direction of motion (d) What is the overall average acceleration for the total time? magnitude       ft/s2 direction      ---Select--- in the direction of motion opposite to the direction of motion

An object moving with uniform acceleration has a velocity of 11.0 cm/s in the positive x-direction when its x-coordinate is 3.06 cm. If its x-coordinate 2.15 s later is −5.00 cm, what is its acceleration? _____cm/s2   A ball is thrown directly downward with an initial speed of 7.45 m/s, from a height of 30.3 m. After what time interval does it strike the ground? _______s A small mailbag is released from a helicopter that is descending steadily at 2.78 m/s. (a) After 3.00 s, what is the speed of the mailbag? v = ______m/s (b) How far is it below the helicopter? d = ______m (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 2.78 m/s? v=______m/s d=______m   A model rocket is launched straight upward with an initial speed of 44.0 m/s. It accelerates with a constant upward acceleration of 1.00 m/s2 until its engines stop at an altitude of 200 m. (a) What can you say about the motion of the rocket after its engines stop? (b) What is the maximum height…

NASA has fired a rocket straight up into the air from ground level with an unknown initial velocity. It reaches a maximum height of 164,000 feet. This happened in Cape Canaveral therefore the rocket is under the acceleration of Earth's gavity in which we all know is -32 ft/sec/sec.                                           Please round your answers to two decimal places. a). Find the time it takes for the rocket to reach maximum height. b). find the initial velocity necessary to reach that height.