A ball is launched with an initial velocity of 44.1 meters per second, at an angle of 34.4 above horizontal. At the peak of its trajectory, what are the components of the ball's velocity vector? vec[vz] = -24.9m/s. vec[vy] = 36.4m/s Ovec vz] = 36.4m/s. vec[vy] = 0m/s Ovec vz] = 36.4m/s, vec[vy] = 24.9m/s vec vz] = 24.9m/s. vec vy] = 0m/s -

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Chapter1: Units, Trigonometry. And Vectors
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A ball is launched with an initial velocity of 44.1 meters per second, at an angle of
34.4" above horizontal. At the peak of its trajectory, what are the components of the
ball's velocity vector?
vec[vz] = - c[vy] = 36.4m/s
24.9m/s.ve
O veclvz] = 36.4m/s, vec[vy] = 0m/s
O veclvz] =
36.4m/s, veclvl = 24.9m/s
O veclvz] = 24.9m/s. veclvy] = Om/s
Transcribed Image Text:A ball is launched with an initial velocity of 44.1 meters per second, at an angle of 34.4" above horizontal. At the peak of its trajectory, what are the components of the ball's velocity vector? vec[vz] = - c[vy] = 36.4m/s 24.9m/s.ve O veclvz] = 36.4m/s, vec[vy] = 0m/s O veclvz] = 36.4m/s, veclvl = 24.9m/s O veclvz] = 24.9m/s. veclvy] = Om/s
Gabriel kicks a soccer ball so that it has an initial velocity 22 meters per second, at an
angle of 16" above the ground. How much time does it take for the soccer ball to
reach its maximum height?
O 0.77 s
O 2.16 s
O 2.24 s
O 0.62 s
Transcribed Image Text:Gabriel kicks a soccer ball so that it has an initial velocity 22 meters per second, at an angle of 16" above the ground. How much time does it take for the soccer ball to reach its maximum height? O 0.77 s O 2.16 s O 2.24 s O 0.62 s
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