A ball has a diameter of 46 mm and falls in honey with terminal velocity of 0.3 m/s. For honey, take p = 1360 kg/m³ and ₁= 0.04 m²/s. Note: The volume of a sphere is V=m³ (Figure 1) Part A Determine the mass of the ball. Express your answer to three significant figures and include the appropriate units. m = 6.32 μA 3 kg Submit Previous Answers Request Answer ?

given: d = 46 mm = 0.046m V = 0.3 m/s ρₕ = 1360 kg/m³ υₕ = 0.04 m²/s Volume of ball = 4/3πr³ ⇒Vₛ = 43×π×(0.0462)³ ⇒Vₛ = 5.0965 x 10-5 m³The terminal velocity of ball having density ρₛ falling inside the fluid honey having density ρₕ and kinematic viscosity υₕ is expressed as V = (ρₛ-ρₕ)gd²18υₕ ⇒0.3 = (ρₛ-1360)×9.81×0.046²18×0.04 ⇒10.4056 = ρₛ - 1360 ⇒∴ ρₛ = 1370.4056 kg/m³since density of sphere ( ball) is ρₛ = mass/ volume = mₛ/Vₛ ⇒1370.4056 = mₛ5.0965×10-5 ⇒mₛ = (1370.4056)*(5.0965x10-5) ⇒mₛ = 0.0698 kg Hence mass of ball(sphere) is 0.0698 kg

Answered: A ball has a diameter of 46 mm and falls in honey with terminal velocity of 0.3 m/s. For honey, take p = 1360 kg/m³ and ₁= 0.04 m²/s. Note: The volume of a…

Elements Of Electromagnetics

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Author: Sadiku, Matthew N. O.

Publisher: Oxford University Press

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A ball has a diameter of 46 mm and falls in honey with a terminal velocity of
0.3 m/s. For honey, take ph = 1360 kg/m³ and h = 0.04 m²/s. Note: The
volume of a sphere is V=³. (Figure 1)
Figure
1 of 1
Part A
Determine the mass of the ball.
Express your answer to three significant figures and include the appropriate units.
Mi
m= 6.32
μА
kg
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