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A bag has 10 marbles in it. 4 are Red, 1 are Green and 5 are Blue. You select 2 marbles, one at a time without replacement. Answer with a decimal rounded to two decimal places. p(red and green) = .04 p( blue and blue) = p( blue and not blue = p( red / not red)

A bag has 10 marbles in it. 4 are Red, 1 are Green and 5 are Blue. You select 2 marbles, one at a time without replacement. Answer with a decimal rounded to two decimal places. p(red and green) = .04 p( blue and blue) = p( blue and not blue = p( red / not red)

A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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A bag has 10 marbles in it. 4 are Red, 1 are Green and 5 are Blue. You select 2 marbles, one at a time without replacement. Answer with a decimal rounded to two decimal places. p(red and green) = .04 p( blue and blue) = p( blue and not blue = p( red / not red)
Transcribed Image Text:A bag has 10 marbles in it. 4 are Red, 1 are Green and 5 are Blue. You select 2 marbles, one at a time without replacement. Answer with a decimal rounded to two decimal places. p(red and green) = .04 p( blue and blue) = p( blue and not blue = p( red / not red)
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