A B D E F G 17. The root node is 18. Three nodes that are siblings are and 19. The terminal nodes are 20. The node with only one child is
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- Please c++ only. Correct answer will upvoted else downvoted. In this problem statement, tree is an undirected associated diagram where there are no cycles. This issue is about non-established trees. A leaf of a tree is a vertex that is associated with all things considered one vertex. The landscaper Vitaly grew a tree from n vertices. He chose to manage the tree. To do this, he plays out a number of tasks. In one activity, he eliminates all leaves of the tree. Note the uncommon instances of the activity: applying an activity to an unfilled tree (of 0 vertices) doesn't transform it. applying an activity to a tree of one vertex eliminates this vertex this vertex is treated as a leaf. applying an activity to a tree of two vertices eliminates both vertices (both vertices are treated as leaves). Vitaly applied k tasks successively to the tree. What number of vertices remain? Input :The main line contains one integer t (1≤t≤104) — the number of experiments. Then, at that point, t…Draw the BST where the data value at each node is an integer and the values are entered in the following order: 36, 22, 10, 44, 42, 60, 50, 70, 80, 85, 75, 55, 45 (Computer Science Exercise: shape [★★★] Write a function same_shape : 'a tree -> 'b tree -> bool that determines whether two trees have the same shape, regardless of whether the values they carry at each node are the same. Hint: use a pattern match with three branches, where the expression being matched is a pair of trees. please use Ocaml for the coding
- typedef struct node{int data;struct node *left,*right;}BST;The node structure of BST is shown above. Please design an efficient algorithm to return the maximum keyword value in BST. Completion function: int findmax (BST *T)D G C E Show the sequences of nodes that result from a depth-first traversal of the graph starting at node C. A. Sequence is: C; G; B; A; D. B. Sequence is: C; D; F; G; A; E; B O C. Sequence is: C; D; F; A; E; G; B D. None of the aboveTask: Complete the function getMinDepth (Node *root), the function takes the root of a tree and returns the minimum depth of the tree. int getMinDepth(Node *root){ //write your code here } Constraints: The number of nodes in the tree is in the range [0, 100000]. -1000 <= Node.val <= 1000
- What is a child node?A tree is implemented using a node structure defined as: struct node{ int data; struct node *left; strict node *right; }; Write a function whose prototype is: int smallest(struct node *); which accepts a tree (pointer to the root) and returns the smallest node in the right sub-tree of the root. If root is NULL, or if there is no right sub-tree, returm the number -999.If the new node to be inserted is 200, identify the sequence of nodes that are visited and the location of the node. 200 100 300 50 150 250 350 250 O 200, as 200's left child 200 -- 300 -250, as 250's right child O 200 - 300 -- 250 - 250, as 250's left child O 200 - 300 250 -250, as 250's right child
- 12:34 A cs61a.org Implement add_d_leaves, a function that takes in a Tree instance t and a number v. We define the depth of a node in t to be the number of edges from the root to that node. The depth of root is therefore 0. For each node in the tree, you should add d leaves to it, where d is the depth of the node. Every added leaf should have a label of v. If the node at this depth has existing branches, you should add these leaves to the end of that list of branches. For example, you should be adding 1 leaf with label v to each node at depth 1, 2 leaves to each node at depth 2, and so on. Here is an example of a tree t (shown on the left) and the result after add_d_leaves is applied with v as 5. 3 2 3 2 4 4 5 5 5 Hint: Use a helper function to keep track of the depth! def add_d_leaves(t, v): """Add d leaves containing v to each ng38. Which of the following nodes should be the root of Tree A so that nodes B and I will be of the same level? Tree A A. node D C. node F B. node E D. node G 384. Write the recurrence relation for the reverse(L) function: append (x, L) { Node curr = L; while(curr != null && curr.next != null) { curr = curr.next; } curr.next = x; } reverse(L){ if(L null) { == return null; } else { Node front L; Node rest = L.next; L.next null; Node restReversed reverse(rest); append (font, restReversed); } }