(a) At 95% confidence, test to determine if it can be concluded that taking the course will increase typing speeds of the secretaries. State the null and alternative hypothesis (b) Provide a 95% confidence interval for ud.
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- A poll was conducted to determine the popularity of a 3D game creation software that was targeted to be launched in three months. Online interviews with 1200 young adults were conducted which revealed that 45% said they would purchase the new software. The margin of error was ±3 percentage points. What is the needed sample size to obtain a 96% confidence interval estimate of the percentage of the targeted young adults who will purchase the new software by allowing the same level of margin of error?A random sample of 169 New Englanders revealed that 154 wear a mask when they are indoors and not in their home. Find and interpret a 95% confidence interval for the proportion of New Englanders who wear a mask. Round your final answer to 2 decimal places. We are 95% confident the proportion of New Englanders that wear a mask is between _______% and ______ %. Please show all work showing how you got the answer so i can better understand thank you!A survey by the society of Human Resource Management asked 350 job seekers why employees change jobs so frequently. The answer selected most (126 times) was "higher compensation elsewhere" as the reason for changing jobs. Then the 95% confidence interval estimate for the population proportion of job seekers who would select "higher compensation elsewhere" as the reason for changing jobs is approximately.
- A study investigated ways to prevent staph infections in surgery patients. The researchers examined a random sample of 100 patients admitted to various hospitals for surgery. They found that 53 of these patients tested positive for Staphylococcus aureus, a bacterium responsible for most staph infections. Construct a 80% confidence interval for the proportion of all patients admitted for surgery who are carriers of S. aureus. Round your answers to three decimal places, and use four decimal places for any interim calculations. We are 80% confident that the interval ( of all patients admitted for surgery who are carriers of S. aureus. contains the true population proportion pA performance analyst simulated a computer system a total of 10 times, each simulation run independent of all the others. She calculated and recorded the sample means for system response time from each of the 10 runs, coming up with the following data: 2,5,17,3,9,6,4,25,8,1(a) What is the confidence interval with a 95% confidence level for the mean response time? (b) The performance analyst was concerned that the width of the confidence interval was too large, and consulted one of her colleagues (who never took simulation and modeling). He assured her that the width of the confidence interval was large because of the two large "outliers," the values 17 and 25, and that she could reduce the width of the confidence interval simply by discarding these values. She tried this, and discovered that the width of the interval did indeed go down substantially. Is this a valid method? Why or why not?A researcher wants to estimate the true proportion of Americans who suffer side-effects after taking a particular medication. A 99% confidence interval for the true proportion of Americans who suffer side-effects after taking the particular medication was found to be (0.024, 0.160). If a hypothesis test is conducted with the hypotheses, H,: p = 0.10 vs H: p# 0.10 , what would be the most likely conclusion? Select one: a. There is very strong evidence that p 0.10. Ob. There is little to no evidence that p = 0.10. c. There is little to no evidence that p # 0.10. d. Cannot tell.
- A researcher is concerned with the effects of various courses that uses LMS and holding online exam with the academic standing. Exams results of students majoring in engineering that uses LMS are taken and analyzed. Is there a difference in the scores of students in various courses that uses LMS at 90% confidence level?Math 010 (Differential Calculus):327629853389 Math 013 (Linear Algebra): 728198216313 Math 016 (Calculus 1): 982134883854 Math 017 (Calculus 2): 727326934263 Math 019 (EDA): 562978135049 In your solution paper, show the null and alternative hypothesis, calculation of sum of squares and mean of square and the F values.A random sample of 212 high school students in a particular town showed that 56 smoke on a regular basis. Find the 95% confidence interval estimating the population percentage for smokers at this high school. Suppose the national average for smokers in high schools is 34.2%. Does it appear that the students in this particular town smoke less than the national average? Justify your answerA sample of size n=79 Is drawn from a population whose standard deviation is o = 29, Part 1 of 2 (a) Find the margin of error for a 90% confidence interval for l. Round the answer to at least three decimal places. The margin of error for a 90% confidence interval for u is Part 2 of 2 (b) If the sample size weren=44, would the margin of error be larger or smaller? (Choose one) ▼ because the sample size is (Choose one) Larger Smaller
- A survey about allergic reactions revealed that 84 out of randomly selected 158 people exhibit allergic symptoms. The percentage of the whole country is believed to be 25% for such allergic symptoms. Find the test statistic for hypothesis testing at right tail. (Sensitivity 0.00)A study was done to determine whether there is a relationship between snoring and the risk of heart disease. Among 1,105 snorers in the study, 85 had heart disease, while only 21 of 1,379 nonsnorers had heart disease. In USE SALT (a) Determine a 95% confidence interval that estimates p, - p2 difference in proportions of snorers and nonsnorers who have heart disease. (Let p, be the proportion of snorers and p, be the proportion of nonsnorers. Round your answers to three decimal places.) |-0.079 X to -0.045This is a 3 part question please help!