
Advanced Engineering Mathematics
10th Edition
ISBN: 9780470458365
Author: Erwin Kreyszig
Publisher: Wiley, John & Sons, Incorporated
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Transcribed Image Text:Determine whether each of the following sequences (an) converges, and
find the limit of each convergent sequence. Name any results or rules that
you use. You may use the basic null sequences listed in Theorem D7 from
Unit D2.
(a) an =
(b) an
(c) an =
4(2n) + 3n4 +6
3(2n) +n4+2n³¹
n5 + 3n² + 2n
2
4n4 + 2n² - n
n = 1, 2, ...
n = 1, 2, ...
n² + 3n² + 2(n!)
n³ + 2n² + (−1)n (n!)'
n = 1, 2, ...

Transcribed Image Text:We now show that there are various basic types of sequences that are null.
By applying the rules from the previous subsection to these 'basic null
sequences', we can deduce the existence of many different null sequences
without having to use the definition.
It is important that you are familiar with these types of basic null
sequences and are able to use them. Reading the proof that they are null
may help you with this, but skim read it if you are short of time and
return to it when time permits.
Theorem D7 Basic null sequences
The following sequences are null.
(a) (1/nº), for p > 0.
(b) (c), for c| < 1.
(c) (nºch), for p > 0, c < 1.
(d) (cn/n!), for c E R.
(e) (nº/n!), for p > 0.
Proof (a) To prove that (1/nº) is null for p > 0, we apply the Power
Rule to the sequence (1/n), which we know is null.
(b) To prove that (c) is null for c < 1, first note that it is sufficient to
consider only the case 0 ≤ c < 1, because any sequence (an) is null if
and only if the sequence (an) is null.
If c= 0, then the sequence is obviously null. Thus we can assume that
0 < c < 1, so we can write
where a > 0.
C =
1
1 + a
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