(A) = a. dim(RS (A)) b. Basis(CS (A)) dim(CS (A)) a. Basis 12. The number of leading variables in the solution of AX=0 will be c. nullity (A) d. Non of these 13. The number of free variables in the solution of AX=0 will be: a. Basis b. rank(A) b. rank(A) unique solution c. nullity (A) c. dim(RS (A)) s dim(CS (A)) d. Non of these M d. dim(NS (A)) =
(A) = a. dim(RS (A)) b. Basis(CS (A)) dim(CS (A)) a. Basis 12. The number of leading variables in the solution of AX=0 will be c. nullity (A) d. Non of these 13. The number of free variables in the solution of AX=0 will be: a. Basis b. rank(A) b. rank(A) unique solution c. nullity (A) c. dim(RS (A)) s dim(CS (A)) d. Non of these M d. dim(NS (A)) =
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 16EQ
Related questions
Question
![11. rank(A) =
a. dim(RS (A))
dim(CS (A))
b. Basis(CS (A))
a. Basis
c. unique solution d. Non of these
12. The number of leading variables in the solution of AX=0 will be
c. nullity (A)
d. Non of these
13. The number of free variables in the solution of AX=0 will be:
a. Basis
b. rank(A)
c. nullity (A)
d. Non of these
14. Set of all ordered
b. rank(A)
c. dim(RS (A)) s dim(CS (A))
d. dim(NS (A)) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1652026a-6ba6-42d7-9e35-ad3e7516e1ec%2F24bebce8-518e-48f7-930f-ce20b8e046cd%2Fft978qi_processed.png&w=3840&q=75)
Transcribed Image Text:11. rank(A) =
a. dim(RS (A))
dim(CS (A))
b. Basis(CS (A))
a. Basis
c. unique solution d. Non of these
12. The number of leading variables in the solution of AX=0 will be
c. nullity (A)
d. Non of these
13. The number of free variables in the solution of AX=0 will be:
a. Basis
b. rank(A)
c. nullity (A)
d. Non of these
14. Set of all ordered
b. rank(A)
c. dim(RS (A)) s dim(CS (A))
d. dim(NS (A)) =
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