College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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(a) A small light fixture on the bottom of a swimming pool is 0.86 m below the surface. The light emerging from the still water forms a circle on the water surface. What is the
diameter of this circle? (Give your answer, in m, to at least two decimal places.)
m
(b) What If? If a 1.58 cm thick layer of oil (noil
1.35) is spread uniformly over the surface of the water, what is the diameter of the circle of light emerging from the swimming
pool? (Give your answer, in m, to at least two decimal places.)
m
=
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Transcribed Image Text:(a) A small light fixture on the bottom of a swimming pool is 0.86 m below the surface. The light emerging from the still water forms a circle on the water surface. What is the diameter of this circle? (Give your answer, in m, to at least two decimal places.) m (b) What If? If a 1.58 cm thick layer of oil (noil 1.35) is spread uniformly over the surface of the water, what is the diameter of the circle of light emerging from the swimming pool? (Give your answer, in m, to at least two decimal places.) m =
The figure below shows the path of a light beam through several slabs with different indices of refraction. (n4 = 1.01)
(a) If 0₁
=
0₁
O
102
n = 1.60
n = 1.40
n = 1.20
114
35.0°, what is the angle 02 of the emerging beam?
(b) What must the incident angle 0₁ be to have total internal reflection at the surface between the medium with n = 1.20 and the medium with n4 = 1.01?
O
expand button
Transcribed Image Text:The figure below shows the path of a light beam through several slabs with different indices of refraction. (n4 = 1.01) (a) If 0₁ = 0₁ O 102 n = 1.60 n = 1.40 n = 1.20 114 35.0°, what is the angle 02 of the emerging beam? (b) What must the incident angle 0₁ be to have total internal reflection at the surface between the medium with n = 1.20 and the medium with n4 = 1.01? O
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