(a) A small amber bead with a mass of 20.0 g and a charge of -0.74 μC is suspended in equilibrium above the center of a large, horizontal sheet of glass that has a uniform charge density on its surface. Find the charge per unit area on the glass sheet (in pc/m2). Tuc/m2 (b) What If? What are the magnitude and direction of the acceleration of the piece f amber if its charge is doubled? (Enter the magnitude in m/s2.) m/s² magnitude direction Select--

345 159 A-140.1 mC charge is placed at the center of a hollow conducting sphere. Find the charge density (in C/m²) on the outside of the sphere if its radius is 5.09 cm and if it contains zero net charge.

Two point charges q1 and q2 are 3.15 m apart, and their total charge is 22 µC. Note that you may need to solve a quadratic equation to reach your answer. (a) If the force of repulsion between them is 0.10 N, what are the two charges (in µC)? smaller value  µCl arger value  µC (b) If one charge attracts the other with a force of 0.457 N, what are the two charges (in µC)? smaller value  µC larger value  µC

I cant seem to get the force calculation

(a) A small amber bead with a mass of 14.4 g and a charge of -0.65 μC is suspended in equilibrium above the center of a large, horizontal sheet of glass that has a uniform charge density on its surface. Find the charge per unit area on the glass sheet (in μC/m²). μC/m² (b) What If? What are the magnitude and direction of the acceleration of the piece of amber if its charge is doubled? (Enter the magnitude in m/s².) magnitude m/s² direction -Select---

A charge q = 1 μC is located at the tip of a hollow cone (such as an ice cream cone without the ice cream) with surface charge density o = 6.4 μC/m². The slant height of the cone is L = 4 mm, and the half-angle at the vertex is 0: 10⁰. = L12 L/2 If the top half of the cone is removed and thrown away, what is the force (in Newton's) on the charge 9 due to the remaining part of the cone?

11:09 d G . O 图“自 Ritesh Sah 2. A uniform rod oflength L lies on the x-axis as shown. The rod has a net charge of Q that is uniformly spread alongits length. Q=+5.00e-9 C L= 5.00 meters A uniformly charged rod of length L on the x-axis. Point P is at (5,2) meters on the x,y plane. Use the methods shown in class to: • Calculate the magnitude/size of the electric field at point P due to the rod. Calculate the Trig Angle, measured counter-clockwise from the +x-axis in degrees, of the electric field at point P due to the rod.

Density, density, density. (a) A charge -328e is uniformly distributed along a circular arc of radius 6.00 cm, which subtends an angle of 72°. What is the linear charge density along the arc? (b) A charge -328e is uniformly distributed over one face of a circular disk of radius 3.50 cm. What is the surface charge density over that face? (c) A charge -328e is uniformly distributed over the surface of a sphere of radius 2.00 cm. What is the surface charge density over that surface? (d) A charge -328e is uniformly spread through the volume of a sphere of radius 3.30 cm. What is the volume charge density in that sphere? (a) Number Units (b) Number Units (c) Number Units (d) Number Units

What is the y (vertical) component of the force exerted on charge qc by charges qa and qb?

A 26.3-g mass is suspended 4.35 cm above a nonconducting flat plate, directly above an embedded charge of q.  a) If the mass has the same charge, q, how much must q be so that the mass levitates (just floats, neither rising nor falling)? b) If the charge q is produced by adding electrons to the mass, by how much will the mass be changed?