(a) A random sample of 200 voters in a town is selected, and 109 are found to support an annexation suit. Find the 96% confidence interval for the fraction of the voting population favoring the suit. (b) What can be asserted with 96% confidence about the possible size of the error if the fraction of voters favoring the annexation suit is estimated to be 0.71? This problem uses normal probability table, like area under normal curve. How do I find z distribution? In the problem I'll find that zα/2 = z0.02 = 2.05, but I don't know how to get 2.05, since the only chart provided is the normal probability table.
(a) A random sample of 200 voters in a town is selected, and 109 are found to support an annexation suit. Find the 96% confidence interval for the fraction of the voting population favoring the suit. (b) What can be asserted with 96% confidence about the possible size of the error if the fraction of voters favoring the annexation suit is estimated to be 0.71? This problem uses normal probability table, like area under normal curve. How do I find z distribution? In the problem I'll find that zα/2 = z0.02 = 2.05, but I don't know how to get 2.05, since the only chart provided is the normal probability table.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.2: Expected Value And Variance Of Continuous Random Variables
Problem 10E
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(a) A random sample of 200 voters in a town is selected, and 109 are found to support an annexation suit. Find the 96% confidence interval for the fraction of the voting population favoring the suit.
(b) What can be asserted with 96% confidence about the possible size of the error if the fraction of voters favoring the annexation suit is estimated to be 0.71?
This problem uses normal probability table, like area under normal curve.
How do I find z distribution? In the problem I'll find that zα/2 = z0.02 = 2.05, but I don't know how to get 2.05, since the only chart provided is the normal probability table.
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