a) → a = qvB m b)→ blâ= a qvB m ○ c)→. a = qm vBJ ○ d) → qm a = vB

A charged particle is entering a squared region of space with a uniform magnetic field. The sides of the region are 6 m wide. The particle enters the region exactly in the middle of one of the sides in a direction perpendicular to it, as in the Figure below. The charge of the particle is q = 20.0μC, its mass is m = 6.0 × 10-¹6 kg, and the velocity of the particle is |v| = 5 × 10³ m/s. How strong is the magnetic field so that the particle escapes such region in a direction perpendicular to the one it entered? See Figure for more details. XX XXXXXX :XXXXXXX XX XXX:

A particle having mass m = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is given an initial velocity in the −y direction (downward), as shown in the figure, of v = 3.65E2 m/s. Everywhere in space there is a uniform constant magnetic field B = 0.340 T pointing in the +z direction, which is out of the plane of the page. What is the radius of the cyclotron orbit trajectory that this particle will move along (in m)?

A particle having mass m  = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is given an initial velocity in the −y direction (downward), as shown in the figure, of v = 7.84E2 m/s. Everywhere in space there is a uniform constant magnetic field B = 0.340 T pointing in the +z  direction, which is out of the plane of the page. What is the speed of the particle after 7 periods of the cyclotron motion (in m/s)?

A long straight wire suspended in the air carries a conventional current of 7 amperes in the -x direction as shown (the wire runs along the x-axis). At a particular instant an electron at location m has velocity m/s. z out (a) What is the magnetic field due to the wire at the location of the electron? B = tesla (b) What is the magnetic force on the electron due to the current in the wire? F= N (c) If the moving particle were a proton instead of an electron, what would the magnetic force on the proton be? F =

A uniform magnetic field B = 1.7 x 10-4 T exists in +x direction. A proton (q = +e,  and mp = 1.67 x 10-27 kg) is shot through the field in the +y direction with a speed of 3.5 x 105 m/s. Find the magnitude and direction of the magnetic force FB on the proton.

A particle having mass m = 2.80E-4 kg carries a negative charge q= −1.70E-6 C . The particle is given an initial velocity in the −y direction (downward), as shown in the figure, of v = 2.41E2 m/s. Everywhere in space there is a uniform constant magnetic field B = 0.340 T pointing in the +z direction, which is out of the plane of the page. What is the the magnetic force that B exerts on the particle (in N; use positive sign if the force points in the +x direction and negative sign if the force points in the −x direction)?