a a 12.5 2 10 Ω 120 V 30 15Ω 20 N ww

Q: Homework: 10 2 6 V 42 8 V us F1)

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Q: 2. Find Vo. 10Ω V. 2Ω 1:3 30 ww 1245°V 5Ω ell ll

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Q: I, 1.2 kW 0.8 KVAR (cap) 100/90° V (+ 2 kVA 4 kW 0.707 pf leading 0.9 pf lagging

A: The solution is given below

Q: 20,000 Ω 5000 Ω +60 V - 2 V 1V -60 V Ως 9Ω 12Ω νo

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Q: Determine v, 3 V 2.2 k + +8 V Si -8 V

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Q: 11. R 요 equivalent AO R, R 1200 1200 J00 BO

A: To find the equivalent resistance

Q: Determine the voltage V, for the network. 9 12 V 912 V Si Si Ge V,+0.3 V 0.3 V 0.7 V 2.2 k2 2.2 k2

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Q: 3Ω 60 V 10 A 1Ω 2Ω 2Ω 1Ω . 1Ω 22.5 4Ω 5 A +1

A: For the given circuit I0 is calculated as shown below

Q: t= 0 + Vx – ww 10 mF 2 A 3Ω 6Ω 20V ww

A: find the time constant for the given RC circuit ?

Q: 1 = 0 120 V 330N i38 mH 320

A: The current in inductor for t>0

Q: Calculate VAB 10 V A 9.3 V B 1.4 V 8.6 V A 11 Si Si B RL 1 kohms D Si с R2 1 kohms 12

A: In this question we will find voltage across point AB.

Q: ww 5Ω A 16 2 10 2 Vo 12 V

A: Here I have applied superposition theorom to get the answer.

Q: 12/0* v 10 10 ww 10 2/0 A A

A: We are authorized to answer one question at a time, since you have not mentioned which question you…

Q: +12 V +Vpp lo Rp 860 0 Vg = 0 V Ro R$ 390 n 10 MO

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Q: a a 12.5 2 10Ω 52 ww 120 V 30 2 15 2 20 2 b b ww ww

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Q: I. + Vs (600 v Ip 120 V 21. 20 19 tos -torr

A: Since you have asked multiple questions in a single request, we will be answering only the first…

Q: 6 S II V V. V: 10 S 32 A 12 S 24 A

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Q: 4 S 6 S ww ww 9 A (A v 21S 2 S 3 S

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Q: 12 V 5.6 kΩ V, oH Z. β= 100 8os 25 μS 390 kΩ Z; 8 V

A: Dear student as per our guidelines we are supposed to solve only one question in which it should…

Q: 1. Determine the numerical value of the current I. 18 A 30 V 2Ω 72 V 6 A 4 Ω

A: The value of current I in the circuit below:

Q: 9.0 V I 40 Ω ww 50 Ω

A:

Q: 3 2 5 2 + 2 2 8 A 20 V +

A: We will apply krichoff's current law and voltage division rule  to find out the voltage.

Q: 20 Ω j 202 ww lll 8V, 3 /0° A 202

A: According to the question we have to calculate the value of Vx.

Q: 2/0° Α (Υ + 1) Ω (W + 3) Ω 2 Ω Μ j4 Ω 4/0° A 10/90° V ΤΩ

A: Given- W=5  Y=0 We have to use mesh analysis method.

Q: Answer: I, = 0.5 mA 12 kn 4 mA 12 ka ww 12 ΚΩ 6 V 12 kn

A:

Q: 1000 v2/0 ( w= 377

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Q: 52 10 2 V1 A 20 v(+ 10 2 4 A VTh

A:

Q: ξ5Ω 3/0° A 8Ω -/2Ω ww 20 Ω 31x 10Ω 40/90° V j15 Ω j4 Q whel

A: 1. effect of the voltage source, Open-circuit the current source, Ix will be, -40∠90=8-j2+10+j4Ix…

Q: Determine the value of load resistance for maximum power transfer in the given circuit. 560 2 IK N…

A: The value of the load resistance for the maximum power transfer in the given circuit.

Q: 20 2 20 H 10 Ω ww ww mm rell V/5 10 Ω

A:

Q: 4. Determine Vo. O 12 V si Y 2.2 ka

A:

Q: A 10 B 5.0 Il 3V1 vi 1 211 8V

A: Given circuit shown

Q: (b) eT 8(t – T) dt ejwT 8(t – T) dt

A: The given expression is, Using property,

Q: t ter 32 32 ww -o a 15 V 4 A 62 90

A: Here across ab i have found the norton equivalent circuit.

Q: ト Vi V. C2 Given: R= 10ks * 10 uF 1 mF

A:

Q: 8 A 8Ω 2Ω 10 N 100 V 4 0 3Ω

A:

Q: 1.5 Q 1.5O 120 V 21 2 105 V İA

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Q: 10 N 10 Ω 2Ω 4Ω + V 5V, 3 A 1Ω 7Ω 9Ω () 9 A

A: By krichoff's law we will find out voltage

Q: 1 = 0 v(1) 8A 4 A 40 N 15 N 3100 34 (5 H) 312 (20 H).

A: Transient response is the response of a system which is the change in transient(equilibrium) or…

Q: 10 Ω 4 V ww iz 10 v (* 12 V 3Ω is 6 V

A:

Q: 6. T(s) = 1.05 x 107 s² +1.6 x 10³s + 1.05 x 107

A:

Q: Determine i, using Nodal Analysis 1 kQ at 2 mA ( ↑ 5 kQ R R=8 kN

A: We will apply KCL at node to find node voltage. Now using ohms law we will find current Io.…

Q: a 120 V 3Ω 6 A 2Ω od +1

A: Given

Q: 24 V 10 V 2 H t = 0 (+1) ww

A:

Q: The voltage v(t) across the 40 resistor is 2 H 4Ω (Ο 8A 27 cos(5t+30°) V V(1) LF 52 50

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Q: り2 |.8 A ( ↑ 8 V 152 102

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Q: 2Ω ww- ww Ix Is O 12 O 6 О з0 O 18 O 24 601 PM

A:

Q: Determine the value of the Current 13. +1 12 V + ww 892 + {! 9 V ww 20 92 13

A: Voltage across 8 ohm resistor is 12V and across 20 ohm resistor is 9 volts. we can make use of KCL…

Q: 10N 2.50 80 V 30 n

A:

Current Division Method

The generalized current divider formula is given by the following relation below,