(a) A 1.00 cm-high object is placed 4.05 cm to the left of a converging lens of focal length 7.35 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position height x Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm in front of the second lens ✓ X Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm Is the image inverted or upright? Ⓒupright O inverted Is the image real or virtual? O real virtual (b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position? distance cm direction to the left v

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(a) A 1.00 cm-high object is placed 4.05 cm to the left of a converging lens of focal length 7.35 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging
lens. Find the position and height of the final image.
position
height
inverted
Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm
in front of the second lens ✓
Is the image inverted or upright?
O upright
Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final
image. cm
real
virtual
Is the image real or virtual?
(b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance
(in cm), and in which direction, that the object must be moved from its original position?
distance
cm
direction
to the left
Transcribed Image Text:(a) A 1.00 cm-high object is placed 4.05 cm to the left of a converging lens of focal length 7.35 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position height inverted Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm in front of the second lens ✓ Is the image inverted or upright? O upright Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm real virtual Is the image real or virtual? (b) What If? If an image of opposite characteristic, i.e., virtual if the image in part (a) is real and real if the image in part (a) is virtual, is to be obtained, what is the minimum distance (in cm), and in which direction, that the object must be moved from its original position? distance cm direction to the left
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