A 76.0 mL sample of 0.0100 M HIO4 is titrated with 0.0200 M RbOH solution. Calculate the pH after the following volumes of base have been added.(a) 14.1 mLpH = 3.32(d) 39.9 mLpH = 9.58XX(b) 37.2 mLpH = 4.79(e) 69.5 mLpH = 10.79XX(c) 38.0 mLpH = 7

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A 76.0 mL sample of 0.0100 M HIO4 is titrated with 0.0200 M RbOH solution. Calculate the pH after the following volumes (a) 14.1 mL pH = 3.32 (d) 39.9 mL pH = 9.58 X X (b) 37.2 mL pH = 4.79 (e) 69.5 mL pH = 10.79 X X (c) 38.0 mL pH = 7

A 76.0 mL sample of 0.0100 M HIO4 is titrated with 0.0200 M RbOH solution. Calculate the pH after the following volumes (a) 14.1 mL pH = 3.32 (d) 39.9 mL pH = 9.58 X X (b) 37.2 mL pH = 4.79 (e) 69.5 mL pH = 10.79 X X (c) 38.0 mL pH = 7

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

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A 76.0 mL sample of 0.0100 M HIO4 is titrated with 0.0200 M RbOH solution. Calculate the pH after the following volumes of base have been added.
(a) 14.1 mL
pH = 3.32
(d) 39.9 mL
pH = 9.58
X
X
(b) 37.2 mL
pH = 4.79
(e) 69.5 mL
pH = 10.79
X
X
(c) 38.0 mL
pH = 7

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