A 75.0 kg man stands on a platform scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.20 m/s in 1.00 s. It travels with this constant speed for the next 10.00 s. The elevator then undergoes a uniform acceleration in the negative y direction for 1.70 s and comes to rest. What does the scale register: (d) during the time it is slowing down? Take g = 10 ms-2

A 65kg gymnast jumps on the trampoline. At the lowest point of her motion, the trampoline is depressed .50m below equilibrium. what is her approximate upward acceleration at this point?

A crate of mass m = 24 kg rides on the bed of a truck attached by a cord to the back of the cab as in the figure below. The cord can withstand a maximum tension of 64 N before breaking. Neglecting friction between the crate and truck bed, find the maximum acceleration the truck can have before the cord breaks. (Enter the magnitude of the maximum acceleration in the forward direction.) m/s?

A child on a toboggan sits at rest on the top of a tobogganing hill. If the child travels 70.0 m [downhill] in 5.3 s while accelerating uniformly, what acceleration does the child experience?

A basketball player jumps straight up for a ball. To do this, he lowers his body 0.310 m and then accelerates through this distance by forcefully straightening his legs. This player leaves the floor with a vertical velocity sufficient to carry him 0.940 m above the floor. (a) Calculate his velocity (in m/s) when he leaves the floor. (Enter a number.) m/s (b) Calculate his acceleration (in m/s²) while he is straightening his legs. He goes from zero to the velocity found in part (a) in a distance of 0.310 m. (Enter a number.) m/s² (c) Calculate the force (in N) he exerts on the floor to do this, given that his mass is 104 kg. (Enter a number.) N

6. A skydiver of mass m = 60 kg leaps from a plane with an initial upward velocity of vo = +5 m/s. Assume the diver experiences air resistance proportional and opposite to their velocity, with drag coefficient b= 11 N/(m/s). Also assume acceleration due to gravity is g = 9.8 m/s². The velocity of the diver changes with time, as modelled by the following differential equation. m = -mg-bv dv dt Solve for u(t)= the velocity of the diver at time t, and determine the diver's terminal velocity: lim v(t) t-x

1. A golf ball is hit from ground level with initial velocity given x(t)= 3 m/s(t) in a direction that is due east and at an angle theta above the horizontal. Neglecting air resistance, use Newton's second law to find the position as a function of time, using coordinates with x measured east and y north. Find the time for the golf ball to return to the ground and how far it travels in that time.

Decont M ts. Using Newton's second law to calculate the acceleration of a key hanging in a car. You tape one end of a piece of string to the ceiling light of your car and hang a key with mass m on the other end of the string, A protractor taped to the light allows you to the angle the string makes with the vertical. Your friend drives the car while you make measurements. When the car has a constant acceleration with magnitude a toward the right, the string hangs at rest (relative to the car), making an angle ß with the vertical. (a) Derive an expression for the acceleration a in terms of the mass m and the measured angle B. (b) In particular, what is a when B = 45°? When B=0? Show your work that leads to your answer. Explain each step in your work to get the full credit. The equation with no ts. Calculate the magnitude and explanation will get your answer zero point. (c) bo direction of the total force acting on your body when the measured angle B is 45 degree or B = 45⁰. Assume the…