V₁A700 90° AV 2400 vVA0.032-90° A70R220 Nv = 100Sin (w: - 45)B8.24L-35° AleXc150B0.08/ -90° AFind Ipс14.28 45° AC0.054 20° AD50 L120° AD2) القيمة العظمى للتيارما0.014 60° AE6.48 L-45°/تیار دا0.4L

In this question, we need to determine the current IP in first circuit and current IR in the…

A 700L80° A 1220 v A 008 0 7a 10 n v = 100Sin(wt – 45) B 8.24 L-35° A xe 150 0 B nn8, 90° A Find Ip c 14.28 450 A 0.054 / 0° A D 50 L1200 A D القيمة العظمى للتيارما 0.014 /60° A E 6.48 L-45°/ تیار lx ا 0.4 L

A 700L80° A 1220 v A 008 0 7a 10 n v = 100Sin(wt – 45) B 8.24 L-35° A xe 150 0 B nn8, 90° A Find Ip c 14.28 450 A 0.054 / 0° A D 50 L1200 A D القيمة العظمى للتيارما 0.014 /60° A E 6.48 L-45°/ تیار lx ا 0.4 L

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

V₁
A
700 90° A
V 2400 v
V
A
0.032-90° A
70
R
220 N
v = 100Sin (w: - 45)
B
8.24L-35° A
le
Xc
150
B
0.08/ -90° A
Find Ip
с
14.28 45° A
C
0.054 20° A
D
50 L120° A
D
2) القيمة العظمى للتيارما
0.014 60° A
E
6.48 L-45°/
تیار دا
0.4L

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