A −6.20−6.20-DD lens is held 13.5cm13.5cm from an ant 1.00mm1.00mm high. Find the image distance. Follow the sign conventions.

A 1.00-cm-high object is placed 4.30 cm to the left of a converging lens of focal length 8.45 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 188.8 height 26.048 X cm in front of the second lens X cm

An object of height 9.00 cm is placed 26.0 cm to the left of a converging lens with a focal length of 10.5 cm. Determine the image location in cm, the magnification, and the image height in cm. HINT (a) the image location in cm cm (b) the magnification (c) the image height in cm cm (d) Is the image real or virtual? real virtual (e) Is the image upright or inverted? upright inverted

You are tasked with sourcing a lens which will be made out of glass with refractive index 1.668, and is submersed in a liquid with refractive index 1.379. You want a focal length of 6.5 cm, and the radius of curvature of the first side of the lens is 7.4 cm. What radius of curvature is required for the second side, in cm? [Note the first/second lens surface radius is conventionally positive/negative for convex.]