A 5KVA, 240/120 V single phase transformer has the following parameters: R1 = 0.06 Q R2 = 0.015 Q X1 = 0.18 Q X2 = 0.045 2 Rc =2000 Q Xm = 400 0 Transformer secondary winding feeds an inductive load of 5KVA power factor 0.9 at 120V rated voltage. Way using the L equivalent circuit given, find the primary voltage, primary current and apparent power factor of the transformer. What is the efficiency of the transformer? R,+R2 X,+X2 mm V1= V l1 = A Im V1 Ret V2 V2 cose = Xm1 n = % a

A 5KVA, 240/120 V single phase transformer has the following parameters: R1 = 0.06 Q R2 = 0.015 Q X1 = 0.18 Q X2 = 0.045 2 Rc =2000 Q Xm = 400 0 Transformer secondary winding feeds an inductive load of 5KVA power factor 0.9 at 120V rated voltage. Way using the L equivalent circuit given, find the primary voltage, primary current and apparent power factor of the transformer. What is the efficiency of the transformer? R,+R2 X,+X2 mm V1= V l1 = A Im V1 Ret V2 V2 cose = Xm1 n = % a

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.16P: A single-phase, 50-kVA,2400/240-V,60-Hz distribution transformer has the following parameters:...

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