A 57Fe nucleus at rest emits a 14.0-keV photon. Use conservation of energy and momentum to find the kinetic energy of the recoiling nucleus in electron volts. Use Mc2 = 8.60 × 10-9 J for the final state of the 57Fe nucleus.

A 57Fe nucleus at rest emits a 14.0-keV photon. Use conservation of energy and momentum to find the kinetic energy of the recoiling nucleus in electron volts. Use Mc2 = 8.60 × 10-9 J for the final state of the 57Fe nucleus.

Modern Physics

3rd Edition

ISBN:9781111794378

Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Publisher:Raymond A. Serway, Clement J. Moses, Curt A. Moyer

Chapter3: The Quantum Theroy Of Light

Section: Chapter Questions

Problem 32P

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de Broglie Equation

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Question

A ⁵⁷Fe nucleus at rest emits a 14.0-keV photon. Use conservation of energy and momentum to find the kinetic energy of the recoiling nucleus in electron volts. Use Mc² = 8.60 × 10^-9 J for the final state of the ⁵⁷Fe nucleus.

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