A 502 transmission line is terminated with a 502 resistor on series with a 2 * 10 7H inductor. If the frequency of the operation is 60 * 10° MHz find the reflection coefficient at the load. Select one: O a. 0 O b. 0.45e22 O c. 1 O d. 0.36e56 O e. 0,6e 37
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- A supply of 240V-50HZ feeds a highly inductive load of 502 through thyristor bridge that is half-controlled. What is the load power factor when the firing angle delay is 45°? A. 0.6565 B. 0.5566 C. 0.6655 D. 0.5656 1igatioConvert the complex number W = 25e-0.6435 into a. Polar Form b. Rectangular Form c. Trigonometric FormAn inductor is attached to an AC voltage source. Which change will result in a halving of the current?A. Halving the voltage and doubling the frequencyB. Doubling the frequencyC. Halving the frequencyD. Doubling the voltage and halving the frequency
- The angle of separation between each point on the twiddle factor unit circle for N=64 is O pi/16 O pi/64 O pi/8 pi/32Calculation discrepancy with Smith chart: I am trying to find the input impedance for a load that is 10 -30j where Zo = 50 for a quarter wave transform. When I calculated it the answer is 25 + 75j or 0.5 + 1.5j but when I used the Smith Chart I get 10 + 1.7j. Why am I getting 2 different answers, is the Smith Chart wrong?The Jwitch in the craut, seea in below has been in position a" for a lag hime. At t=o, the sutch mores instantancausly to posikon "b". Fird Volt) and iole) fortzo 1oma 20kn 5 MA Solan to 多
- 6. What is the effect of load inductance on the ripple current? 7. i effect of chonnine Bock and boost 8. Wh 9 What chopping 10. At what duty evcle does the load current rinnle current heA clipper is a device that removes either the positive half (top half) or negative half (bottom half), or both positive and negative halves of the input AC signal. In other words, a clipper is a device that limits the positive amplitude or negative amplitude or both positive and negative amplitudes of the input AC signal. In some cases, a clipper removes a small portion of the positive half cycle or negative half cycle or both positive and negative half cycles. In the below circuit diagram, the positive half cycles are removed by using the series positive clipper. QUESTION: In your own opinion. Why do we need to clip a certain amount of voltage in positive or negative or on both sides? What is the benefit of that in our devices or circuits in doing such thing?Identify which measurement this oscilloscope time difference reading is useful for. Oscilloscope-XSC1 Channel_B Channel_A 169.064 V 113.590 V -55.474 V Time T1 Reverse 250.000 us 89.282 V 122.375 V 33.093 V T2 382.576 us T2-T1 132.576 us Save Ext. trigger Timebase Scale: 200 us/Div X pos. (Div): 0 Channel A Scale: 100 V/Div Y pos. (Div): 0 Channel B Trigger Scale: 100 V/Div Y pos. (Div): 0 Edge: f 2 AB Ext Level: Y/T Add B/A A/B AC0 DC AC0 DC Single Normal Auto None O none of the above O phase shift O period
- Q.2) Determine all values of resistors and capacitor for the triangular waveform generator whose output alternates between +10Vpeak and -10V peak when the input is a 10-Hz square wave that alternates between +2V and -2V. The input resistance to the generator must be at least 15 kQ. you may assume that there is no de component or offset in the input.phase The conductirs in a singke line are 6m above the guünd. gnünd. Each conductrs are spaced 3m a pant. Calculate the capacitance Capaci tance per milo, of the live if' bothe thu conductors radii s 75 mum. a.erdudlirg ground ef fet (ufvestal) b. mcluding gound effed.find the instantane ous expressions or the applied voltage V, voltage voltage figure. Als draw across resistos Vp and across aeross capaciter the phaser diengram. Vc in Ve R= 62 iz1o 5z sin (6250t)