A 500 Ohm, 200 Ohm, and 300 Ohm resistors are all in serles and connected to 100 V power supply. What is the potential difference across the 200 Ohm resistor? O 20 V O 30 V O 100 V 50 V

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A 500Ohm, 200 Ohm, and 300 Ohm resistors are all in series and connected to 100 V power supply. What is the potential difference across the 200 Ohm resistor?

### Series Resistor and Potential Difference Problem

**Problem Statement:**

A 500 Ohm, 200 Ohm, and 300 Ohm resistors are all in series and connected to 100 V power supply. What is the potential difference across the 200 Ohm resistor?

**Options:**
1. 20 V
2. 30 V
3. 100 V
4. 50 V

---

#### Explanation:

When resistors are connected in series, the total resistance \(R_t\) is the sum of individual resistances:
\[ R_t = R_1 + R_2 + R_3 \]

Therefore,
\[ R_t = 500 \, \Omega + 200 \, \Omega + 300 \, \Omega = 1000 \, \Omega \]

The total current \(I\) in the circuit can be found using Ohm's Law:
\[ I = \frac{V}{R_t} = \frac{100 \, V}{1000 \, \Omega} = 0.1 \, A \]

Next, to find the potential difference across the 200 Ohm resistor, we use Ohm's Law again:
\[ V_2 = I \times R_2 \]
\[ V_2 = 0.1 \, A \times 200 \, \Omega = 20 \, V \]

Thus, the potential difference across the 200 Ohm resistor is 20 V.

**Correct Answer:** 1. 20 V

---

This problem illustrates key principles in analyzing circuits with resistors in series and demonstrates practical application of Ohm's Law in determining the voltage drops across individual resistors.
Transcribed Image Text:### Series Resistor and Potential Difference Problem **Problem Statement:** A 500 Ohm, 200 Ohm, and 300 Ohm resistors are all in series and connected to 100 V power supply. What is the potential difference across the 200 Ohm resistor? **Options:** 1. 20 V 2. 30 V 3. 100 V 4. 50 V --- #### Explanation: When resistors are connected in series, the total resistance \(R_t\) is the sum of individual resistances: \[ R_t = R_1 + R_2 + R_3 \] Therefore, \[ R_t = 500 \, \Omega + 200 \, \Omega + 300 \, \Omega = 1000 \, \Omega \] The total current \(I\) in the circuit can be found using Ohm's Law: \[ I = \frac{V}{R_t} = \frac{100 \, V}{1000 \, \Omega} = 0.1 \, A \] Next, to find the potential difference across the 200 Ohm resistor, we use Ohm's Law again: \[ V_2 = I \times R_2 \] \[ V_2 = 0.1 \, A \times 200 \, \Omega = 20 \, V \] Thus, the potential difference across the 200 Ohm resistor is 20 V. **Correct Answer:** 1. 20 V --- This problem illustrates key principles in analyzing circuits with resistors in series and demonstrates practical application of Ohm's Law in determining the voltage drops across individual resistors.
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