Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- 2) A large 3-phase, 4000 Va (phase to phase), 60 Hz squirrel-cage induction motor draws a current of 385 A/phase. The total active power at the stator input terminals is 2344 kW, when operating at full load. The corresponding speed is accurately measured and found to be 709.2 r/min. The stator is connected in wye and the resistance between two stator terminals is 0.10 Q. The total iron losses are 23.4 kW and the windage and friction losses are 12 kW. Calculate the following: c) The total 1²-R losses in the rotor d) The load mechanical power (kW), torque (kN•m), and efficiency. S = Va · V3 - I S= Vy•3·I %3Darrow_forwardHury up pleaaaaaaasearrow_forwardV1 = 170 V f1 = 100 Hz 1) A single-phase load has an active power of P = 2 kW at V1 V @f1Hz and the power factor is cosφ = 0.75. This motor iscompensated to cosφ = 0.85 using a parallel capacitor Reactive power and apparent power after compensation?arrow_forward
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