College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.90 mm. A 15.0-V potential difference is applied to these plates. (a) Calculate the electric field between the plates.kV/m(b) Calculate the surface charge density.nC/m2(c) Calculate the capacitance.pF(d) Calculate the charge on each plate.pCarrow_forwardAn air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 2.20 mm. (a) If a 15.0 V potential difference is applied to these plates, calculate the electric field between the plates. 33 Your response differs from the correct answer by more than 100%. kV/m (b) What is the surface charge density? 80.45 Your response differs from the correct answer by more than 10%. Double check your calculations. nC/m² (c) What is the capacitance? 3.1 pF .(d) Find the charge on each plate. Enter a number. differs from the correct answer by more than 10%. Double check your calculations. pCarrow_forwarda. A potential difference of 5.00 V is placed across a 43.1 mF capacitor. How much charge is stored in the capacitor? b. In the case of part (a), how much energy is stord in the 43.1 mF capacitor with a 5.00 V potential difference across its plates?arrow_forward
- A spec of dust with a static charge of +2 Coulombs is in between the plates of a parallel plate negatively charged plate. The electric field in the capacitor is meter. How much work would capacitor, where it rests on the 2200 Volts/meter, and the separation between the plates is 0.01 be done in moving the spec from the negative plate to the positive plate? O 4.4 V O 6.6V 2.2 V O -1.9 V O none of thesearrow_forwardy R The figure above represents a thin, circular ring of radius R= 5.8 m. The ring has a uniformly distributed charge Q=3.4 pC and point P is x = 14.8 m away from the center of the ring. (k = 9x10° V -m -c-1,p = 10-0) a) Calculate the electric potential value at point P and express your answer in SI units. Vp= V b) Calculate the electric field at point P. Ep=arrow_forwardAn electron is released from rest at the negative plate of a parallel plate capacitor and accelerates to the positive plate (see the drawing). The plates are separated by a distance of 1.7 cm, and the electric field within the capacitor has a magnitude of 2.8 x 106 V/m. What is the kinetic energy of the electron just as it reaches the positive plate? Electric field Electron KE positive + + + + + + + +arrow_forward
- The ammonia molecule NH3 has a permanent electric dipole moment equal to 1.47 D, where 1 D = 1 debye unit = 3.34 x 10-30 C.m. Calculate the electric potential in volts due to an ammonia molecule at a point 56.2 nm away along the axis of the dipole. (Set V = 0 at infinity.) Number i Unitsarrow_forwardA parallel plate capacitor is charged to a potential of 3000 V and then isolated. Find the magnitude of the charge on the positive plate if the plates area is 0.40 m2 and the distance between the plates is 0.020 m. Group of answer choices 68 µC 54 µC 27 µC 18 µCarrow_forwardA parallel-plate capacitor in air has a plate separation of 1.58 cm and a plate area of 25.0 cm2. The plates are charged to a potential difference of 270 V and disconnected from the source. The capacitor is then immersed in distilled water. Assume the liquid is an insulator. (a) Determine the charge on the plates before and after immersion. before pC pC after (b) Determine the capacitance and potential difference after immersion. Cf = F AV = V (c) Determine the change in energy of the capacitor. nJ Need Help? Read Itarrow_forward
- A parallel plate capacitor has a potential difference between its plates of 1.6 V and a plate separation distance of 2.5 mm. What is the magnitude of the electric field if a material that has a dielectric constant of 3.4 is inserted between the plates? O 290 V/m O 110 V/m O 170 V/m O 240 V/m O 190 V/marrow_forwardRegarding the Earth and a cloud layer 800 m above the Earth as the "plates" of a capacitor, calculate the capacitance. Assume the cloud layer has an area of 1 km2 and that the air between the cloud and the ground is pure and dry. nF Assume charge builds up on the cloud and on the ground until a uniform electric field of 2.0 106 N/C throughout the space between them makes the air break down and conduct electricity as a lightning bolt. What is the maximum charge the cloud can hold? Carrow_forward
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