A 5.00 kg block is at rest on an inclined surface at angle 0 = 30.0° . The block is at rest and not sliding down the surface. Determine the magnitude of the frictional force in this experiment. (g=9.81 m/s²) L 98.0 N 49.0 N 24.5 N 42.4 N

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A 5.00 kg block is at rest on an inclined surface at angle 0 = 30.0°. The block is at rest and not
sliding down the surface. Determine the magnitude of the frictional force in this experiment. (g=9.81
m/s?)
L
98.0 N
49.0 N
24.5 N
42.4 N
Transcribed Image Text:A 5.00 kg block is at rest on an inclined surface at angle 0 = 30.0°. The block is at rest and not sliding down the surface. Determine the magnitude of the frictional force in this experiment. (g=9.81 m/s?) L 98.0 N 49.0 N 24.5 N 42.4 N
Expert Solution
Step 1

Given data

The block's mass is: m = 5 kg

The angle of inclination is: θ=30°

 

The free-body diagram for the above configuration is shown below:

Physics homework question answer, step 1, image 1

The block is at rest on an inclined surface. The expression for the frictional force is given as:

fr=mgsinθ

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