Related questions
Question
A 5-kg mass is suspended vertically by a massless string of length 2.00 m length from the ceiling. A force of 45.0 N is applied horizontally at the midpoint of the string. What is the angle the string makes with the vertical in equilibrium? Show the Free-Body Diagram. ( Take g = 9.8 m/s2 )
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps with 2 images
Knowledge Booster
Similar questions
- A force is applied to an initially stationary block of mass 5.70 kg that sits on a horizontal floor as shown. The 57.0 N force is applied at 0 = 44° angle. The coefficients of friction %3D between the floor and the block are u, F 0.519 and u, = 0.279. What is the acceleration %3D of the block? Use g=9.8 m/s?.arrow_forwardTwo blocks each of mass m = 3.90 kg are fastened to the top of an elevator as in the figure below. (a) If the elevator accelerates upward at 1.6 m/s?, find the tensions T1 and T2 in the upper and lower strings. T1 88.92 T2 44.46 N N (b) If the strings can withstand a maximum tension of 99.0 N, what maximum acceleration can the elevator have before the first string breaks? Your response differs from the correct answer by more than 10%. Double check your calculations. m/s? 1.60 m/s m D marrow_forwardA 3200 kg helicopter is flying horizontally. A 250 kg crate is suspended from the helicopter by a massless cable that is constantly 20 degrees from vertical. What propulsion force F prop is being provided by the helicopter's rotor? Air resistance can be ignored. Give your answer in component form in a coordinate system where ι^ points in the direction of motion and j^ points upwardarrow_forward
- The figure below shows a box with a mass of m= 3.90 kg on a ramp inclined at an angle of 35.0°. The coefficient of static friction between the box and the ramp is 0.250. Find the minimum magnitude of the force F (in N), applied to the box in a direction perpendicular to the ramp, that will prevent the box from sliding down the ramp. N m 35.0°arrow_forwardAnswer the question correctly. Thank you!arrow_forwardAn elevator of mass 300 kg is caused to accelerate upward at 2.5 m/s2 by a force in the cable that supports it. What is the force exerted by the cable (in N) ?arrow_forward
- Two blocks with masses m1= 50 kg , m2= 100 kg are connected with a rope. Blocks are pulled with a 20.0 N force making a=30.0 degree angle withhorizontal on a frictionless surface. first question: Show all the forces on the two blocks by drawing a seperate diagram for each block. second question: apply the newton rules and find the tension (T=?) in the rope in between the two blocks.arrow_forwardA block of mass M is suspended at rest by two strings attached to walls, as shown in the figure. The left string is horizontal with tension force T2 and and the right string with tension force T1 makes an angle 0 with the horizontal. g is the magnitude of the gravitational acceleration. Which of the following relationship is true? Select all apply. T1 OT1sine+(-T2) = 0 OTitane+ (-Mg) = 0 OT1cose+(-Mg) = 0 O Tısine + (-Mg) = 0arrow_forwardA 60 kg block slides along the top of a 100 kg block. The lighter block has an acceleration of 3.8 m/s2 when a horizontal force F= 390 N is applied. Assuming there is no friction between the bottom 100 kg block and the horizontal frictionless surface but there is friction between the blocks. Find the acceleration of the 100 kg block during the time the 60 kg block remains in contact.arrow_forward
arrow_back_ios
arrow_forward_ios