A 5 kg block attached to a spring with a spring constant of 8 N/m oscillates horizontally on a frictionless table. Its velocity is 7 m/s when x0 = 0.43 m. What is the speed of the block when x1 = 0.08 m?

Q: A spring with spring constant 94 N/m and rest length 27.2 cm is used to pull a wooden block of…

A: GIven data The spring constant is given as k = 94 N/m. The rest length is given as l = 27.2 cm. The…

Q: A 1500-kg car moving at 25 m/s hits an initially uncompressed horizontal spring with spring constant…

A:

Q: A vertical spring with elastic constant 95 N/m is compressed by 25 cm, and an object of mass 350 g…

A:

Q: OK, once again we have a pendulum, this time of length 1.14 m, which you release from rest at an…

A:

Q: A block with mass m =6.3 kg is hung from a vertical spring. When the mass hangs in equilibrium, the…

A:

Q: simple pendulum is suspended from the ceiling by means of a string and the pendulum has a length of…

A:

Q: Question 14 A 2.24 kg box, sliding on a frictionless horizontal surface, has a speed of 1.02 m/s…

A:

Q: The figure shows two springs (k1 = 10 N/m and k2 = 20 N/m ) attached to a block that can slide on a…

A:

Q: Q2) A block of mass m= 1.09 kg is pushed against an ideal, massless spring with spring constant k=…

A: m=1.09 kg k=10.5 N/m x1=-1.96 m let the speed at equilibrium be v

Q: A 0.25-kg block along a horizontal track has a speed of 1.5 m/s immediately before colliding with a…

A:

Q: An inclined plane of angle e=20° has a spring of force constant k=500 N/m fastened securely at the…

A:

Q: A block that is connected to a horizontal spring is allowed to oscillate, and a graph of its…

A: Given that:

Q: A large toy car is pushed horizontally by a spring, and the spring has a spring constant of 135 N/m.…

A: Spring constant K = 135  N/m  Let the mass of the toy car be m  Compression in spring is Xi = 0.055…

Q: Problem: An object of mass m=0.20 kg is suspended from the ceiling on a spring of relaxed length 40…

A: a) Let the equilibrium be after spring elongates ∆y. At this position we have,…

Q: The horizontal surface on which a block slides is frictionless. The speed of the block is 6.0 m / s…

A: Here, ∆K=-UsKf-Ki=Ui-Uf      (Ui=0)Kf=Ki-Uf=12mvi2-12kxf2

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in…

A:

Q: A 0.20−kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a…

A: givenm=0.2 kgAt 2.3 cm from equillibriumKinetic energy ,(KE)=1.5 JPotential energy ,(PE)=2.3 J

Q: 12 The horizontal surface on which a 2 kg block slides is frictionless. The speed of the block…

A:

Q: When a 2 kg mass is suspended from a spring the spring stretches 24.5 cm. What is the spring…

A: Given : m = 2 kg x = 24.5 cm = 0.245 m

Q: A 0.500-kg cart connected to a light spring for which the force constant is 23.5 N/m oscillates on a…

A:

Q: OK, once again we have a pendulum, this time of length 1.92 m, which you release from rest at an…

A: Given data: Length of the pendulum, L=1.92 m    θ1=58.3 ∘  θ2=11.7 ∘

Q: A block is suspended from a vertical spring which causes it to stretch by 10.0cm from its…

A: The elastic potential energy of the spring is, U=12kx2k=2Ux2 Substitute the values, to find the…

Q: A bullet with mass 5.18 g is fired horizontally into a 1.918-kg block attached to a horizontal…

A: (a) The spring energy is equal to the kinetic energy of the system, since all kinetic energy is…

Q: A block of mass of 1.0 kg is moving across a frictionless floor and comes in contact with an ideal…

A: Given data :                Mass of the block , m = 1 kg                Velocity of the block,  v =…

Q: what is its speed (in m/s) when it is a distance of 10 cm from the equilibrium position

A: If we apply conservation of energy  Then  Initiay energy = final energy Initial energy is for…

Q: A block attached to an ideal spring oscillates without friction on a horizontal table. A student…

A: Given data:   Mass (m) = 1.64 kg Maximum velocity (vmax) = 4.11 m/s Required: Maximum kinetic energy…

Q: If a spring has a constant of 950 N/m and a length of 18 cm at equilibrium position, what is the…

A: Given data:  Spring constant (k) = 950 N/m Length at equilibrium position = 18 cm Spring stretched…

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in…

A: Write a given value of this question. m=5kgE=22.5J

Q: 10. A block with mass 0.50 kg is forced against a horizontal spring of negligible mass, compressing…

A: In the following question , when block is forced against horizontal spring it will loose some energy…

Q: A marble with a mass of 0.085 kg compresses a spring 5.1 cm. If the spring has a constant k = 150…

A:

Q: A simple pendulum is made from a 0.761-m-long string and a small ball attached to its free end. The…

A:

Q: A horizontal spring-mass system has low friction, spring stiffness 220 N/m, and mass 0.4 kg. The…

A: Given

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in…

A: Given : Total mechanical energy, T.E=22.5 J Mass of block, m= 5 kg

Q: A 1500-kg car moving at 20 m/s hits an initially uncompressed horizontal ideal spring. What is the…

A: The mass of the car is m = 1500 kg. The speed of the car is v = 20 m/s. The compression in the…

Q: OK, once again we have a pendulum, this time of length 1.03 m, which you release from rest at an…

A:

Q: A 1 kg block is attached to a spring with a constant of 100 N/m. The spring is displaced 0.1 m from…

A: A 1 kg block is attached to a spring with a constant of 100 N/m. The spring is displaced 0.1 m from…

Q: Superpós es 8 Determine the shape of the spring at t = 0.2 s, 0.4 s, and 0.6 s. t= 0.0 s t=0.2 s…

A:

Q: 9. A vertically mounted spring (k = 900 N/m) is compressed by 24.0 cm relative to its unstrained…

A:

Q: A bullet with mass 5.00 g is fired horizontally into a 2.000-kg block attached to a horizontal…

A: Given:- A bullet with mass m1 = 5.00 g = 5 x 10-3 kg  A block mass of m2 = 2.0 kg  The spring has a…

Q: 18. A dart of mass 0.4 kg is pressed against the spring of a toy gun. The spring with a constant K =…

A: The mass m=0.4kg  The spring constant k=160N/m  To find the speed of the dart

Q: A block of mass 1.7 kg is attached to a horizontal spring that has a force constant 1100 N/m as…

A: Solution:

Q: The figure below is for a mass/spring system. The mass is 0.6 kg. v(m/s) 20.0 15.0 10.0 S0 -5.0…

A: NOTE: Since, you have asked multiple sub-parts we can answer only first three sub-parts according to…

Q: A 0.454-kg block is attached to a horizontal spring that is at its equilibrium length, and whose…

A:

Q: OK, once again we have a pendulum, this time of length 1.49 m, which you release from rest at an…

A: GIVEN The length of the pendulum = 1.49 m pendulum release from rest at an angle of 41.6 degrees to…

Q: The horizontal surface on which a 2 kg block slides is frictionless. The speed of the block before…

A:

Q: 38. The work done to compress a spring of modulus of elasticity 4 N to half its original length is…

A: Work done to compress the spring is stored in form of elastic potential energy of spring .Spring…

Q: what is the velocity of the block vf in m/s?

A: Friction will perform negative work and decrease total mechanical energy of spring block system .…

Q: A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in…

A: Given: Mass of the block, m = 5 kg. Total mechanical energy, E = 22.5 J.   To Find: Maximum velocity…

Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.