A 4.15-g bullet is moving horizontally with a velocity of +340 m/s, where the sign+indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1196 g, and its velocity is +0.644 m/s after the bullet passes through it. The mass of the second block is 1518 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision 340 Beco +0.644 -1196 Ar (a) Vlock Number (b) KEtter/KEbeforeNumber Back 2 Pok -1518 4.15 Units Units
A 4.15-g bullet is moving horizontally with a velocity of +340 m/s, where the sign+indicates that it is moving to the right (see part a of the drawing). The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet. The mass of the first block is 1196 g, and its velocity is +0.644 m/s after the bullet passes through it. The mass of the second block is 1518 g. (a) What is the velocity of the second block after the bullet imbeds itself? (b) Find the ratio of the total kinetic energy after the collision to that before the collision 340 Beco +0.644 -1196 Ar (a) Vlock Number (b) KEtter/KEbeforeNumber Back 2 Pok -1518 4.15 Units Units
Transcribed Image Text:A 4.15-g bullet is moving horizontally with a velocity of \(+340 \, \text{m/s}\), where the sign + indicates that it is moving to the right. The bullet is approaching two blocks resting on a horizontal frictionless surface. Air resistance is negligible. The bullet passes completely through the first block (an inelastic collision) and embeds itself in the second one, as indicated in part b. Note that both blocks are moving after the collision with the bullet.
The mass of the first block is \(1196 \, \text{g}\), and its velocity is \(+0.664 \, \text{m/s}\) after the bullet passes through it. The mass of the second block is \(1518 \, \text{g}\).
Tasks:
(a) What is the velocity of the second block after the bullet embeds itself?
(b) Find the ratio of the total kinetic energy after the collision to that before the collision.
### Diagrams
- **Initial Situation**: The bullet with velocity \(+340 \, \text{m/s}\) approaches from the left.
- **Collision with Block 1**: After the bullet passes through Block 1, the block moves with a velocity of \(+0.664 \, \text{m/s}\).
- **Collision with Block 2**: The bullet embeds itself in Block 2, which begins to move.
### Inputs for Solution
- \((a)\) \(V_{\text{Block 2}} =\)
- \((b)\) \(\frac{KE_{\text{final}}}{KE_{\text{initial}}} =\)
Select units for your answers.
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