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A 4.0 m long board with uniform density has mass 75 kilograms and is laid horizontally atop 2 support beams. A 50 kg person is walking to the right on the board.
a. Determine the force that the left support beam exerts on the board when the person is 2.5 m from the left end of the board.
i. What point will you use it as your pivot point to use torques to answer this question? Explain why this is a good choice of a pivot point that allows you to just use torques to determine this force.
ii. Calculate the force.
b. Determine the farthest point on the board that the person can walk before the board loses contact with the left support beam. (Hint: what does it mean if the support force is negative? Is this physically possible?)
c. Determine the maximum mass of the person such that the person can reach the end of the board without the board losing contact with the left support beam causing the board to flip off its support.
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