Related questions
Question
Transcribed Image Text:A 35.0-turn solenoid of length 6.30 cm produces a magnetic field of
magnitude 2.20 mT at its center. Find the current in the solenoid.
A
Need Help?
Read It
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by stepSolved in 2 steps
Knowledge Booster
Similar questions
- Suppose you wish to produce a 2-T magnetic field in a toroid with an iron core for which magnetic susceptibility is x=3 x 10³. The toroid has a mean radius of 18 cm and is wound with 600 turns. Hint с a. What current is required to produce this magnetic field in the iron core? Current of A is needed. b. For comparison, what current is required to produce the same magnetic field in an air-filled toroid of same geometry? Current of While it is not always practical to have region of magnetic field filled with ferromagnetic materials, this dramatic increase in strength of magnetic field produced is useful in some applications you will see in upcoming chapters. Submit Question 4 A is needed for toroid with no iron core. % Search or type URL 5 MacBook Pro < 6 A 6 7 * 8 ( 9arrow_forwardA solenoid of length 2.50 cm and radius 0.750 cm has 33 turns. If the wire of the solenoid has 1.25 amps of current, what is the magnitude of the magnetic field inside the solenoid? magnitude of the magnetic field: 2.07 x10-3 Ignoring the weak magnetic field outside the solenoid, find the magnetic energy density inside the solenoid. magnetic energy density: 1.70 J/m³ What is the total magnetic energy inside the solenoid? 3.19 x10¬6 total magnetic energy: J Incorrectarrow_forwardAn air-core solenoid with 64 turns is 8.00 cm long and has a diameter of 1.20 cm. When the solenoid carries a current of 0.710 A, how much energy is stored in its magnetic field?arrow_forward
- Determine the current I flowing through a solenoid, if the magnetic flux inside its core is found to be 2.90 x 10-4 Wb. The radius of the solenoid is 25.0 cm and the number of turns per meter is 235. Aarrow_forward8. An electromagnet is made by inserting a soft iron core into a solenoid. The solenoid has 1800 turns, radius 2.00 cm, and length 23.5 cm. When 2.00 A of current flows through the solenoid, the magnetic field inside the iron core has magnitude 0.920 T. What is the relative permeability κB of the iron core?arrow_forwardYou have a solenoid with an initial current of 386 A and a turn density of 6088 What is the initial magnetic field through the solenoid? Binitial = 2.95 T The current in the solenoid drops to 51 A over the course of 1.1 ms. What is the final magnetic field through the solenoid? Bfinal = T Inside the solenoid is a coil with 75 loops and a radius of 9.0 cm. The coil is aligned so that the magnetic field from the solenoid passes through the coil perpendicular to the plane of the coil (directly down the center of the coil). What is the magnitude of the induced emf in the 75-turn coil at the center of the solenoid during this change in magnetic field? Enter you answer as a positive number. emf = V The coil has a resistance of 20 2. What is the current through the coil? Icoil A loops m = What is the power dissipated by the coil? Pcoil = Warrow_forward
arrow_back_ios
arrow_forward_ios