A 3000-kg Ferris wheel accelerates from rest to an angular speed of 0.21 rad/s 11 s . Approximate the Ferris wheel as a circular disk with a radius of 24 m . What is the net torque on the wheel? Express your answer using two significant figures.

A 1.756-kg sphere of radius 0.31 m is rotating about an axis through its center at 24.843 rev/s with the angular velocity in the +z direction.  A torque 11.573N∙m acts on the sphere about the center of the sphere in the +x direction.  What is the angular acceleration, in rad2/s, of the sphere? (Isphere = 2/5 MR2)

An automobile engine can produce 253 Nm of torque. Calculate the angular acceleration (in rad/s2) produced if 80.2% of this torque is applied to the drive shaft, axle, and rear wheels of a car, given the following information. The car is suspended so that the wheels can turn freely. Each wheel acts like a 15.0 kg disk that has a 0.180 m radius. The walls of each tire act like a 2.00 kg annular ring that has inside radius of 0.180 m and outside radius of 0.320 m. The tread of each tire acts like a 10.0 kg hoop of radius 0.330 m. The 12.1 kg axle acts like a rod that has a 2.00 cm radius. The 29.7 kg drive shaft acts like a rod that has a 3.20 cm radius. rad/s² t Additional Materials Reading

A circular disk with a radius of 0.38 m is subject to 2 tangentially applied forces. The disc is fixed such that it will rotate about its center. Both forces produce a torque in the same direction. F1 = 3.6 N applied at the outer edge of the disc. F2 = 4.3 N applied at a distance of 0.28 from the center of the disc. What is the net torque on the disc?

A force in the +y direction applied at the point x = 8.1 m, y = 8.1 m gives rise to a torque of 63.7 Nm about the origin. Determine the magnitude of the force. Express your answer in N, to at least one digit after the decimal point. plz help use g = 9.8

As shown below, a 32 kg bar that is 4.1 m long is set up to rotate about its center (the yellow circle). Force B is acting 68 cm from the left end of the bar. A = 34 NB = 45 NC = 32 N?A = 56°?B = 24° Find the individual torque, the net torque, and the direction the bar will rotate. ?A = ?B = ?C = ?net =

Problem 1: A small rubber wheel is used to drive a large pottery wheel. The two wheels are mounted so that their circular edges touch. The small wheel has a radius of 6.5 cm and accelerates at the rate of 7.5 rad/s2 , and it is in contact with the pottery wheel (radius 24.0 cm ) without slipping. Part A Calculate the angular acceleration of the pottery wheel.   Part B Calculate the time it takes the pottery wheel to reach its required speed of 70 rpm .