A 3 kg mass is located at (-3, 3), a 7 kg mass is located at (4, 2) and a 1.2 kg mass is located at (1, -1). (a) Calculate the x coordinate and y coordinate of the center of mass for the mass system. (b) What happens to the center of mass as the 1.2 kg mass is gradually increased?

object of mass m1=10 lbs with a velocity of 10 ft/s is colliding to mass m2=5 lbs with a velocity of 5 ft/s opposite direction. fibd V1 in ft/s if e=0, e=0.8 & e=1.

In the figure below, three masses are positioned as shown. What is the magnitude of F13? у (ст) m,=100 g m2=200 g m3=300 g 5 m2 4 F32 3 F12 F23 F21 m3 m1 1 F31 F13 х (ст) 5 6 0 1 3 4 7 8

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Find the center of mass of a 120-cm long rod, made of 60 cm of iron (density 8.5 g/cm3) and 60 cm of aluminum (density 2.9 g/cm3). Express the location of the center of mass as measured from the left of the rod, assuming that the iron part of the rod is on the left and the aluminum part is on the right.

To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 cm long (measured from the hip joint) by assuming that the upper leg and the lower leg (which includes the foot) have equal lengths and that each of them is uniform. For a 70.0 kg person, the mass of the upper leg is 8.60 kg, while that of the lower leg (including the foot) is 5.25 kg. Find the location of the center of mass of this leg, relative to the hip joint, if it is (a) fully extended, and (b) bent at the knee to form a right angle with the upper leg.

The following equation describes the motion of a rocket that is expelling a total mass M of fuel at a rateα = -dm/dt:dv/dt = uα/(M-αt),where u is the speed the fuel is ejected, v is the velocity of the rocket in the x-direction, and t is time. Assume the velocity at t = 0 is v(0) = v0, and that M, and u are constants. The burn rate is proportional to the mass of the rocket, as follows:α = -βm,where m is the current mass of the rocket (which is therefore time-dependent). This means that as less fuel is available to burn, then the fuel is burned at a lower rate. Write an expression for the mass of the fuel as a function of time.  Now, write an expression for the velocity as a function of time for the rocket. A particular rocket burns fuel at a rate proportional to the mass of the fuel with the constant of proportionality being 6.4 1/s. The propellant speed is 5.1 m/s. The total mass of fuel is 136.4 kg. What is the speed, in meters per second, of the rocket at t = 2.7 s?

How do you find the the center of mass of a lamina whose density is given by p(x, y) on a region R?? Here m is the mass, M, is the moment in the x- axis and My is the moment in the y- axis М, М, Center of mass is located at т m The coordinates of the center are (M2, My) Find the moment M, and divide by the mass m The center of mass is located in the center of the universe. Find the moment M, and divide by moment My о ООО

For the distribution of particles that appear in the plane of the figure, all the particles have the same mass m. Determine a) The coordinates of the center of mass of the system b) The coordinates in which a fourth particle of mass 2m must be placed so that the center of mass of the new system moves to the origin of coordinates.

Solve it correctly please. I will rate accordingly